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College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000

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BuyFindarrow_forward

College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000
Textbook Problem

Unreasonable Results

The relatively scarce naturally occurring calcium isotope 48Ca has a half−life at about 2 × 10 16 y . (a) A small sample of this isotope is labeled as having an activity of 1.0 Ci. What is the mass of the 48Ca in the sample? (b) What is unreasonable about this result? (c) What assumption is responsible?

To determine

(a)

The mass of the 48Ca in the sample.

Explanation

Given info:

The half-life of 48Ca is

  t12=2×1016y

The activity is

  R=1.0Ci

Formula used:

The formula for activity is

  R=0.693Nt12

So the mass is

  N=Rt120.693

Calculation:

Substituting the values

  N=(1.0Ci)×(2× 10 16y)0.693

  N=(1.0×3

To determine

(b)

The cause of unreasonable mass.

To determine

(c)

The cause of the high result of mass.

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