   Chapter 31, Problem 80PE

Chapter
Section
Textbook Problem

Unreasonable ResultsThe relatively scarce naturally occurring calcium isotope 48Ca has a half−life at about 2 × 10 16 y . (a) A small sample of this isotope is labeled as having an activity of 1.0 Ci. What is the mass of the 48Ca in the sample? (b) What is unreasonable about this result? (c) What assumption is responsible?

To determine

(a)

The mass of the 48Ca in the sample.

Explanation

Given info:

The half-life of 48Ca is

t12=2×1016y

The activity is

R=1.0Ci

Formula used:

The formula for activity is

R=0.693Nt12

So the mass is

N=Rt120.693

Calculation:

Substituting the values

N=(1.0Ci)×(2× 10 16y)0.693

N=(1.0×3

To determine

(b)

The cause of unreasonable mass.

To determine

(c)

The cause of the high result of mass.

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Describe diffusion in terms or entropy.

Biology: The Unity and Diversity of Life (MindTap Course List)

Why does nuclear fusion require high temperatures?

Horizons: Exploring the Universe (MindTap Course List)

What organ serves as the principle site for gluconeogenesis?

Chemistry for Today: General, Organic, and Biochemistry

Is it possible to convert internal energy to mechanical energy? Explain with examples.

Physics for Scientists and Engineers, Technology Update (No access codes included) 