   Chapter 5, Problem 12P

Chapter
Section
Textbook Problem

A worker pushing a 35.0-kg wooden crate at a constant speed for 12.0 m along a wood floor does 350 J of work by applying a constant horizontal force of magnitude F0 on the crate. (a) Determine the value of F0. (b) If the worker now applies a force greater than F0, describe the subsequent motion of the crate. (c) Describe what would happen to the crate if the applied force is less than F0.

(a)

To determine
The applied force F0 that pushes the crate at a constant speed.

Explanation

Given Info:

The mass of the crate is 35.0kg .

The distance that the crate is moved is 12.0m .

The work done on the crate is 350J .

Formula to calculate the applied force is,

F0=WF0dcosθ

• WF0 is the work done on the crate
• d is the crate’s displacement
• θ is the angle between displacement vector and the force vector

Since, the displacement is in the direction of the applied force, the angle θ is zero

(b)

To determine
The motion of the crate if the worker applies more force.

(c)

To determine
The motion of the crate if the worker applies less force.

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