   Chapter 5, Problem 13P

Chapter
Section
Textbook Problem

A 70-kg base runner begins his slide into second base when he is moving at a speed of 4.0 m/s. The coefficient of friction between his clothes and Earth is 0.70. He slides so that his speed is zero just as he reaches the base. (a) How much mechanical energy is lost due to friction acting on the runner? (b) How far does he slide?

(a)

To determine
The mechanical energy lost due to friction acting on the runner.

Explanation

Given Info:

The mass of base runner is 70kg .

The speed of base runner is 4.0m/s .

The coefficient of friction between his cloth and earth is 0.70 .

According to the Work-Energy theorem, the net work done on an object is equal to the change in kinetic energy of the object.

W=KEfKEi

• KEf is the finial kinetic energy
• KEi is the initial kinetic energy

Since, the base runner’s speed is zero just as he reaches the base; the finial kinetic energy of the base runner is zero.

Thus,

The energy lost due to friction is,

W=12mvi2

• vi is the initial velocity of the runner

Substitute 70kg for m and 4

(b)

To determine
the distance that the base runner slides before he comes to rest.

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