Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
7th Edition
ISBN: 9780199339136
Author: Adel S. Sedra, Kenneth C. Smith
Publisher: Oxford University Press
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Chapter 5, Problem D5.53P
To determine
To design: A circuit which resembles the given circuit.
The values of
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5. Choose the correct answer: a) The reason of high input resistance of the MOSFET is: 1. The insulator layer. 2. The reverse biasing. 3. The forward biasing. b) Which transistor has no Ipss parameter?. 1. JFET. 2. E-MOSFET. 3. D-MOSFET. ¢) For an n-channel D-MOSFET transistor, at what condition can gm be greater than gmo?. 1. Vs is positive. 2. Vgs is negative. 3. Vas =0. d) A certain amplifier has an Rp=1KQ. When a load resistance of 1KQ is capacitively coupled to the drain, the gain will reduce to the: 1. Half. 2. Quarter. 3. Not change.
Answer as quickly as possible. I'll give upvote. Thank you. The circuit shown is a common source amplifier with a current mirror bias. It is given that the NMOS (M1) parameters are μoCox = 3mA/V2, VTH,n = 0.5V and λ = 0.02 and the PMOS (M2 and M3) parameters are μoCox = 1mA/V2 and VTH,p = −0.6V . The PMOS transistor M3 does not have channel length modulation while PMOS transistor M2 has λ = 0.02. It is also given that the dimensions of M2 and M3 have equal widths of 5µm and lengths of L2 = 3µm and L3 = 1.5µm, respectively. M1 has length of L1 = 1µm and width of W1 = 2µm. Find the gm and ro of transistor M1.
If the inputs A and B are 0 and 1 respectively, Q5 will:
(i) cause the LED to turn off
(ii) a collector-emitter voltage approximately 0 V
(iii) at cut-off
(iv) a negative base-collector voltage
Chapter 5 Solutions
Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
Ch. 5.1 - Prob. 5.1ECh. 5.1 - Prob. 5.2ECh. 5.1 - Prob. D5.3ECh. 5.2 - Prob. 5.4ECh. 5.2 - Prob. 5.5ECh. 5.2 - Prob. 5.6ECh. 5.2 - Prob. 5.7ECh. 5.3 - Prob. D5.8ECh. 5.3 - Prob. D5.9ECh. 5.3 - Prob. D5.10E
Ch. 5.3 - Prob. 5.11ECh. 5.3 - Prob. 5.12ECh. 5.3 - Prob. D5.13ECh. 5.3 - Prob. D5.14ECh. 5.3 - Prob. 5.15ECh. 5.4 - Prob. 5.16ECh. 5.4 - Prob. 5.17ECh. 5 - Prob. 5.1PCh. 5 - Prob. 5.2PCh. 5 - Prob. 5.3PCh. 5 - Prob. 5.4PCh. 5 - Prob. D5.5PCh. 5 - Prob. 5.6PCh. 5 - Prob. D5.7PCh. 5 - Prob. 5.8PCh. 5 - Prob. 5.9PCh. 5 - Prob. 5.10PCh. 5 - Prob. 5.11PCh. 5 - Prob. 5.12PCh. 5 - Prob. 5.13PCh. 5 - Prob. 5.14PCh. 5 - Prob. 5.15PCh. 5 - Prob. 5.16PCh. 5 - Prob. 5.17PCh. 5 - Prob. 5.18PCh. 5 - Prob. 5.19PCh. 5 - Prob. D5.20PCh. 5 - Prob. 5.21PCh. 5 - Prob. 5.22PCh. 5 - Prob. 5.23PCh. 5 - Prob. 5.24PCh. 5 - Prob. 5.25PCh. 5 - Prob. 5.26PCh. 5 - Prob. 5.27PCh. 5 - Prob. 5.28PCh. 5 - Prob. 5.29PCh. 5 - Prob. 5.30PCh. 5 - Prob. 5.31PCh. 5 - Prob. D5.32PCh. 5 - Prob. D5.33PCh. 5 - Prob. 5.34PCh. 5 - Prob. 5.35PCh. 5 - Prob. D5.36PCh. 5 - Prob. 5.37PCh. 5 - Prob. 5.38PCh. 5 - Prob. 5.39PCh. 5 - Prob. 5.40PCh. 5 - Prob. 5.41PCh. 5 - Prob. 5.42PCh. 5 - Prob. 5.43PCh. 5 - Prob. D5.44PCh. 5 - Prob. 5.45PCh. 5 - Prob. D5.46PCh. 5 - Prob. 5.47PCh. 5 - Prob. D5.48PCh. 5 - Prob. D5.49PCh. 5 - Prob. D5.50PCh. 5 - Prob. D5.51PCh. 5 - Prob. 5.52PCh. 5 - Prob. D5.53PCh. 5 - Prob. 5.54PCh. 5 - Prob. 5.55PCh. 5 - Prob. 5.56PCh. 5 - Prob. 5.57PCh. 5 - Prob. 5.58PCh. 5 - Prob. 5.59PCh. 5 - Prob. 5.60PCh. 5 - Prob. 5.61PCh. 5 - Prob. 5.62PCh. 5 - Prob. 5.63PCh. 5 - Prob. 5.64PCh. 5 - Prob. 5.65PCh. 5 - Prob. 5.66PCh. 5 - Prob. 5.67P
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- An npn transistor with IS = 1 × 10−16 μA, αF =0.975, and αR = 0.5 is operating with VB E = 0.70 Vand VBC = 0.50 V. By definition, this transistor isoperating in the saturation region. However, in thediscussion it was noted that this transistor actually behaves as if it is still in the forwardactive region even though VBC > 0. Why? Use thetransport model equations to justify your answerarrow_forwardConsidering the given transistor circuit and given values(β=60; V BE =0,5 V; VCC =15V; R E=1K ; R c=10K ; R1=60K ;R2=30K ).a. Find the base, collector, and emitter currents b. Find the voltage gain of this circuit c. Find the voltage gain by ignoring the capacitor connected to the emitterd. Briefly describe the transistor active zone and state its importancearrow_forward4) By drawing the small signal model of the circuit given below, we can determine the total voltage and current gain values of the circuit, without the bypass capacitor on and without the bypass capacitor. Calculate separately for the two cases as it will be in the circuit (connected to the emitter end of the transistor). (β = 100, rS = 600 Ω, R1 = 27 KΩ, R2 = 4.7 KΩ, RC = 3.3 KΩ, RE = 680 Ω, RL= 15 KΩ, VCC = 10 V)arrow_forward
- Consider the transistor characteristics of Fig. 5.21. (a) Are these the characteristics of a JFET, d-mosfet, or e-mosfet? (b) Make a table of the given Vgs values and the corresponding Id(sat) values. Also include a column in the table giving Id(sat). (c) Make a plot of Id(sat) versus Vgs. Find the slope and y-intercept of the plot and use these to determine values for K and Vt in the model equation Eq. (5.3).ANSWER TO (c) MUST BE K = 1 mA/V2, Vt = −3 Varrow_forward5.1 A 0.18-um fabrication process is specified to have t = 4 nm, µ̟ = 450 cm'/N s, and V, = 0.5 V. Find the value of the process transconductance parameter k. For a MOSFET with minimum length %3D fabricated in this process, find the required value of W so that the device exhibits a channel resistance Ing of 1 k£2 at vos =1 V. %3Darrow_forwardConsider a CE circuit, where trans-conductance is 50mΩ-1, diffusion capacitance is 100 pF, transition capacitance is 3 pF. IB = 20μA. Given base emitter dynamic resistance, rbe = 1000 Ω, input VI is 20*sin(107t). What is the short circuit current gain?arrow_forward
- Answer ASAP. I'll upvote. Thank you. Given: The circuit shown is a common source amplifier with a current mirror bias. It is given that the NMOS (M1) parameters are μoCox = 3mA/V2, VTH,n = 0.5V and λ = 0.02 and the PMOS (M2 and M3) parameters are μoCox = 1mA/V2 and VTH,p = −0.6V . The PMOS transistor M3 does not have channel length modulation while PMOS transistor M2 has λ = 0.02. It is also given that the dimensions of M2 and M3 have equal widths of 5µm and lengths of L2 = 3µm and L3 = 1.5µm, respectively. M1 has length of L1 = 1µm and width of W1 = 2µm. Sketch the small signal model of transistor M3 (Hint: Is there any small signal in any terminal ofM3? If yes, then where is it? If no, then what happens to the small signal model?).arrow_forwardSOLVE NUMBER 2 .1. Solve the output voltage if the gain is 24 db with aninput of 5mV.? 2. Assume a load resistor, RL of 2.2kΩs and a supply voltage of 24v. Calculate the Collector current (Ic) flowing through the load resistor when the transistor is switched fully "ON", assume Vce = 0, & β = 100. Also find the value of the Emitter resistor, Re with a voltage drop of 1.3v across it, R1, R2, and Ib. Assume also a value of 9 times Ib flowing through the resistor R2, while 10 times Ib flowing through R1.arrow_forwardIn the circuit in the figure, VGSQ = 6.8 V, IDQ = 2.4 mA, VGS(Th) = 3.3 V, k = 0.4x10-3 A/V2, RD = 5.6 kΩ, RF = 2.2 MΩ and rd = 25 kΩ. Accordingly, when a RL = 0.1 kΩ load is connected to the output of the circuit, what will be the voltage gain of the circuit? NOTE: MOSFET output resistance must be taken into account in rd calculationsarrow_forward
- For a particular IC-fabrication process, the transconductance parameter k'n = 400 μA/V2, and Vt = 0.5 V. In an application in which vGS = vDS = Vsupply = 1.8 V, a drain current of 2 mA is required of a device of minimum length of 0.18 μm. What value of channel width must the design use?arrow_forwardAn npn transistor with IS = 5 × 10−16 μA, αF =0.95, and αR = 0.5 is operating with VB E = 0.3 Vand VBC = −5 V. This transistor is not truly operating in the region defined to be cutoff, but we still saythe transistor is off. Why? Use the transport modelequations to justify your answer. In what region isthe transistor actually operating according to ourdefinitions?arrow_forwardFind the rout resistance, the ro internal resistance of the mos transistor will not be neglected, transistör Gm vapura are not the samearrow_forward
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