Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
7th Edition
ISBN: 9780199339136
Author: Adel S. Sedra, Kenneth C. Smith
Publisher: Oxford University Press
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Chapter 5.2, Problem 5.7E
(a)
To determine
The range of
(b)
To determine
The range of
(c)
To determine
The range of
(d)
To determine
The values of
(e)
To determine
The value of
(f)
To determine
The value of
To compare: The result obtained with the value found in part (e).
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Please help with this Field-Effect Transistor problem. The problem is typed below, see the attached diagram for reference.
5.57 In the circuit of Fig. P5.57, the NMOS transistor has |Vt| = 0.9 V and VA = 50 V, and operates with VD = 2 V. What it the voltage gain v0/vi? What do VD and the gain become for l increased to 1 mA?
An npn transistor with IS = 1 × 10-16 A, αF =0.975, and αR = 0.5 is operating with VBE = 0.70 V and VBC = 0.50 V. By definition, this transistor is operating in the saturation region. However, in the discussion of Fig. 5.17 it was noted that this transistor actually behaves as if it is still in the forward active region even though VBC > 0. Why? Use the transport model equations to justify your answer.
Since Vcc = 12 V, Vin = 690 mV, RB = 780 kΩ, RC1 = 27.9 Ω, RC2 = 25.4 Ω, RE = 470 Ω, RL = 47 Ω and β1 = β2 = 100 in the circuit in the figure Find the current (IL) flowing through RL?
NOTE-1: VBE1 = VBE2 = 0.7 V will be taken.
NOTE-2: Output impedances of transistors (r0) will be neglected.
Chapter 5 Solutions
Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
Ch. 5.1 - Prob. 5.1ECh. 5.1 - Prob. 5.2ECh. 5.1 - Prob. D5.3ECh. 5.2 - Prob. 5.4ECh. 5.2 - Prob. 5.5ECh. 5.2 - Prob. 5.6ECh. 5.2 - Prob. 5.7ECh. 5.3 - Prob. D5.8ECh. 5.3 - Prob. D5.9ECh. 5.3 - Prob. D5.10E
Ch. 5.3 - Prob. 5.11ECh. 5.3 - Prob. 5.12ECh. 5.3 - Prob. D5.13ECh. 5.3 - Prob. D5.14ECh. 5.3 - Prob. 5.15ECh. 5.4 - Prob. 5.16ECh. 5.4 - Prob. 5.17ECh. 5 - Prob. 5.1PCh. 5 - Prob. 5.2PCh. 5 - Prob. 5.3PCh. 5 - Prob. 5.4PCh. 5 - Prob. D5.5PCh. 5 - Prob. 5.6PCh. 5 - Prob. D5.7PCh. 5 - Prob. 5.8PCh. 5 - Prob. 5.9PCh. 5 - Prob. 5.10PCh. 5 - Prob. 5.11PCh. 5 - Prob. 5.12PCh. 5 - Prob. 5.13PCh. 5 - Prob. 5.14PCh. 5 - Prob. 5.15PCh. 5 - Prob. 5.16PCh. 5 - Prob. 5.17PCh. 5 - Prob. 5.18PCh. 5 - Prob. 5.19PCh. 5 - Prob. D5.20PCh. 5 - Prob. 5.21PCh. 5 - Prob. 5.22PCh. 5 - Prob. 5.23PCh. 5 - Prob. 5.24PCh. 5 - Prob. 5.25PCh. 5 - Prob. 5.26PCh. 5 - Prob. 5.27PCh. 5 - Prob. 5.28PCh. 5 - Prob. 5.29PCh. 5 - Prob. 5.30PCh. 5 - Prob. 5.31PCh. 5 - Prob. D5.32PCh. 5 - Prob. D5.33PCh. 5 - Prob. 5.34PCh. 5 - Prob. 5.35PCh. 5 - Prob. D5.36PCh. 5 - Prob. 5.37PCh. 5 - Prob. 5.38PCh. 5 - Prob. 5.39PCh. 5 - Prob. 5.40PCh. 5 - Prob. 5.41PCh. 5 - Prob. 5.42PCh. 5 - Prob. 5.43PCh. 5 - Prob. D5.44PCh. 5 - Prob. 5.45PCh. 5 - Prob. D5.46PCh. 5 - Prob. 5.47PCh. 5 - Prob. D5.48PCh. 5 - Prob. D5.49PCh. 5 - Prob. D5.50PCh. 5 - Prob. D5.51PCh. 5 - Prob. 5.52PCh. 5 - Prob. D5.53PCh. 5 - Prob. 5.54PCh. 5 - Prob. 5.55PCh. 5 - Prob. 5.56PCh. 5 - Prob. 5.57PCh. 5 - Prob. 5.58PCh. 5 - Prob. 5.59PCh. 5 - Prob. 5.60PCh. 5 - Prob. 5.61PCh. 5 - Prob. 5.62PCh. 5 - Prob. 5.63PCh. 5 - Prob. 5.64PCh. 5 - Prob. 5.65PCh. 5 - Prob. 5.66PCh. 5 - Prob. 5.67P
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- In the circuit given in the picture, the emitter follower is connected to a non-ideal voltage source Vs with a source resistance Rs.These are the value: beta =100Vbe = 0.7VVce,sat = 0V.The sub questions for this problem are:a. If Rs = 0 and Vs = 3V, determine the value of Vo.b. If Rs = 5k Ohms and Vs = 3V, determine the value of Vo.c. If Rs = 5k Ohms , determine the value of Vs that will cause the BJT to start saturating.arrow_forwardSince Vcc = 12 V, Vin = 721 mV, RB = 780 kohm, RC1 = 14.8 ohm, RC2 = 27.5 ohm, RE = 470 ohm, RL = 47 Q2 and B1 = B2= 100 in the circuit in the figure Find the current (1) flowing through RL? NOTE-1: VBE1 = VBE2 = 0.7 V will be taken. NOTE-2: The output impedances (ro) of the transistors will be neglected.arrow_forwardSince Vcc = 12 V, Vin = 690 mV, RB = 780 kΩ, RC1 = 27.9 Ω, RC2 = 25.4 Ω, RE = 470 Ω, RL = 47 Ω and β1 = β2 = 100 in the circuit in the figure Find the current (IL) flowing through RL? NOTE-1: VBE1 = VBE2 = 0.7 V will be taken. NOTE-2: Output impedances of transistors (r0) will be neglected. a. 16,56 mA b. 23,46 mA c. 8,28 mA d. 17,94 mA e. 20,70 mA f. 13,80 mA g. 26,22 mA h. 11,04 mAarrow_forward
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