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The circuit parameters of the diff-amp shown in Figure 11.19 are
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Microelectronics: Circuit Analysis and Design
- the transistor in the circuit above has gm=0.11mS and ro=33Kohm. Given the following condition: R1=770Kohm, R2=890Kohm, RD=5.4Kohm, R3=20Kohm, R6=6.9Kohm, Rsig=2Kohm, determine the input impedance of the amplifier in Kohm.arrow_forwardThe ac equivalent circuit for an amplifier is shown. Assume the capacitors have infinite value, RI =750Ω, RB =100 kΩ, RC =100 kΩ, and R3 =100 kΩ. Calculate the input resistance and output resistance for the amplifier if the BJT Q-point is (75 μA, 10 V). Assume βo =100 and VA =75 V.arrow_forwardConsider the common-source amplifier shown in Figure P11.50. The NMOS transistor has KP=50 μA/V2, L=5 μm, W=500 μm, Vto=1 V and rd=∞.a. Determine the values of IDQ, VDSQ and gm. b. Compute the voltage gain, input resistance, and output resistance, assuming that the coupling capacitors are short circuits for the ac signal. Repeat Problem P11.50 for an NMOS transistor having KP=50 μA/V2, W=600 μm, L=20 μm, Vto=2 V and rd=∞. Compare the gain with that attained in Problem P11.50.arrow_forward
- What is the voltage gain of the common-emitter amplifier as shown? Assume βF = 135, VCC = VEE = 10 V, R1 = 20 kΩ, R2 = 62 kΩ,RC = 13 kΩ, and RE = 3.9 kΩ.arrow_forwardTrue or False Increasing RE improves the CMRR for single-ended output by increasing the differential-mode gain anddecreasing the common-mode gain. Increasing RE reduces the transistor DC currents and increases the DC output voltages. The double-ended output of the differential amplifier is always zero if vs1=vs2 for any value of RE.arrow_forwardPlease complete 1-3 In the Common Emitter Amplifier shown, the emitter current is found to be equal to IE =1mA. Assuming that the collector resistance RC = 1 kΩ, Calculate The internal emitter resistance, r’e. The gain of this amplifier, Av. The voltage gain in dB. Given an input voltage of 50 mV, calculate the output voltage.arrow_forward
- In the circuit in the figure, Vcc = 18 V and RL = 2.2 kΩ, while C1 = C2 = CE = 0.1 μF. It is also known that for parasitic and wiring capacitors, Cwi = 15 pF, Cwo = 21 pF, Cbc = 27 pF, Cbe = 887 pF and Cce = 25 pF. Accordingly, what is the bandwidth of the system? NOTE-1: The output impedance of the transistor r0 will be neglected in the calculations. NOTE-2: The high frequency dependence of hfe, β, will be neglected.arrow_forwardAnswer these questions. Explain Phase inversion of Common Emitter Amplifier. How Common Base Amplifier differs from Common Emitter and Common Collector Amplifier? Calculate Voltage Gain if RC = 150 Ω and RL = 200 Ω, IE = 1.5mAarrow_forwardPlease answer correctly and as soon as possible. I'll give upvote. Thank you. In the common emitter amplifier given, R1=50Ω, R2=1kΩ and CL=1pF. Determine the quiescent collector current, ICQ, needed such that the unity gain frequency, fu, is equal to 2.4 GHz. Show the complete solution and state all assumptions. The BJT parameters are as follows: β→∞,VA→∞, and Cπ=50 femtofarad (fF). Ignore all other parasitic capacitances and use VT=26mV.arrow_forward
- Derive Vo with the given variables. Note that Rv here is a rheostat and is used to vary gain, hence the derivation.arrow_forwardThe ac equivalent circuit for an amplifier is shown . Assume the capacitors have infinite value, RI = 10 kΩ, RG = 1 MΩ, RD = 3.9 kΩ, and R3 = 33 kΩ. Calculate the voltage gain for the amplifier if the MOSFET Q-pointis (2 mA, 7.5 V). Assume Kn = 1 mA/V2 and λ = 0.015 V−1.arrow_forwardFor the circuit shown in Fig. 1 below, the transistor parameters are B =150, VBE =0.7V and VT=26mV. a) Determine the operating point parameters. b) Draw the small signal equivalent circuit based on the re mode c) Determine: i Gain of the transistor, Av Input impedance, Za i. Gain with signal, An V. Output voltage, given that V, =30mVSinotarrow_forward
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