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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

Suppose you eat 28 grams of rhubarb leaves with an oxalic acid content of 1.2% by weight.

  1. (a) What volume of 0.25 M NaOH is required to titrate completely the oxalic acid in the leaves?
  2. (b) What mass of calcium oxalate could be formed from the oxalic acid in these leaves?

(a)

Interpretation Introduction

Interpretation:

The volume of 0.25 M of NaOH required to titrate the oxalic acid in the leaves and the mass of calcium oxalate formed from the oxalic acid in the leaves has to be determined.

Concept introduction:

Rhubarb is a type of plant that contains oxalic acid. It is toxic and corrosive. The stem of Rhubarb is edible and not the leaves as the content of oxalic acid in leaves is quite high.

The acid-base neutralization is the common reaction studied in chemistry. The acids like oxalic acid can be neutralized by a base like NaOH.

Explanation

The volume of 0.25 M of NaOH required to titrate the oxalic acid in the Rhubarb leaves is calculated below.

Given:

The oxalic acid content in 28 grams of Rhubarb leaves is 1.2 % by weight. The mass of oxalic acid is,

m=1.2100×28 g=0.336 g

The number of moles (n) of oxalic acid is calculated as,

n=given massmolar mass

The given mass of oxalic acid is 0.336 g.

The molar mass of oxalic acid is 90.03 g/mol.

Substitute the values,

n=(0.336 g)(1 mol90.03 g)=3.73×103 mol

The balanced chemical equation between oxalic acid and sodium hydroxide is,

H2C2O4(aq)+2NaOH(aq)Na2C2O4(aq)+2H2O(l)

1 mole of oxalic acid requires 2 moles of sodium hydroxide for the neutralization

(b)

Interpretation Introduction

Interpretation:

The mass of Calcium oxalate formed from oxalic acid has to be determined.

Concept introduction:

Rhubarb is a type of plant that contains oxalic acid. It is toxic and corrosive. The stem of Rhubarb is edible and not the leaves as the content of oxalic acid in leaves is quite high.

The acid-base neutralization is the common reaction studied in chemistry. The acids like oxalic acid can be neutralized by a base like NaOH.

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Chapter 17 Solutions

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Sect-17.4 P-17.11CYUSect-17.5 P-17.12CYUSect-17.5 P-17.13CYUSect-17.5 P-17.14CYUSect-17.6 P-17.15CYUSect-17.6 P-17.16CYUSect-17.6 P-1.1ACPSect-17.6 P-1.2ACPSect-17.6 P-1.3ACPSect-17.6 P-1.4ACPSect-17.6 P-1.5ACPSect-17.6 P-2.1ACPSect-17.6 P-2.2ACPCh-17 P-1PSCh-17 P-2PSCh-17 P-3PSCh-17 P-4PSCh-17 P-5PSCh-17 P-6PSCh-17 P-7PSCh-17 P-8PSCh-17 P-9PSCh-17 P-10PSCh-17 P-11PSCh-17 P-12PSCh-17 P-13PSCh-17 P-14PSCh-17 P-15PSCh-17 P-16PSCh-17 P-17PSCh-17 P-18PSCh-17 P-19PSCh-17 P-20PSCh-17 P-21PSCh-17 P-22PSCh-17 P-23PSCh-17 P-24PSCh-17 P-25PSCh-17 P-26PSCh-17 P-27PSCh-17 P-28PSCh-17 P-29PSCh-17 P-30PSCh-17 P-31PSCh-17 P-32PSCh-17 P-33PSCh-17 P-35PSCh-17 P-36PSCh-17 P-37PSCh-17 P-38PSCh-17 P-39PSCh-17 P-40PSCh-17 P-41PSCh-17 P-42PSCh-17 P-43PSCh-17 P-44PSCh-17 P-45PSCh-17 P-46PSCh-17 P-47PSCh-17 P-48PSCh-17 P-49PSCh-17 P-50PSCh-17 P-51PSCh-17 P-52PSCh-17 P-53PSCh-17 P-54PSCh-17 P-55PSCh-17 P-56PSCh-17 P-57PSCh-17 P-58PSCh-17 P-59PSCh-17 P-60PSCh-17 P-61PSCh-17 P-62PSCh-17 P-63PSCh-17 P-64PSCh-17 P-65PSCh-17 P-66PSCh-17 P-67PSCh-17 P-68PSCh-17 P-69PSCh-17 P-70PSCh-17 P-71PSCh-17 P-72PSCh-17 P-73PSCh-17 P-74PSCh-17 P-75PSCh-17 P-76PSCh-17 P-77GQCh-17 P-78GQCh-17 P-79GQCh-17 P-80GQCh-17 P-81GQCh-17 P-82GQCh-17 P-83GQCh-17 P-84GQCh-17 P-85GQCh-17 P-86GQCh-17 P-87GQCh-17 P-88GQCh-17 P-89GQCh-17 P-90GQCh-17 P-91GQCh-17 P-92GQCh-17 P-93GQCh-17 P-94GQCh-17 P-95GQCh-17 P-96GQCh-17 P-97GQCh-17 P-98GQCh-17 P-99GQCh-17 P-100GQCh-17 P-101ILCh-17 P-102ILCh-17 P-103ILCh-17 P-104ILCh-17 P-105ILCh-17 P-106ILCh-17 P-107ILCh-17 P-108ILCh-17 P-109ILCh-17 P-110ILCh-17 P-111ILCh-17 P-112ILCh-17 P-113SCQCh-17 P-114SCQCh-17 P-115SCQCh-17 P-116SCQCh-17 P-117SCQCh-17 P-118SCQCh-17 P-119SCQCh-17 P-120SCQ

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