   Chapter 15, Problem 124AP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
3 views

# Consider the reaction between 1.0 L of 3.0 M AgNO3(aq) and 1.0 L of 1.0 M CuCl2(aq), according to the equation: 2AgNO 3 ( aq )   +  CuCl 2 ( aq ) ) 2AgCl ( s ) + Cu ( NO 3 ) 2 ( aq ) Which of the following will increase the amount of AgCl(s) produced? a. Adding another 1.0 L of 3.0 M AgNO3(aq) h. Adding another 1.0 L of 1.0 M CuCl2(aq) c. Adding 1.0 L of water to the original AgNO(aq) solution d. Allowing all of the water to evaporate from the resulting solution e. At least two of the above will increase the amount of AgCl(s) produced.

Interpretation Introduction

Interpretation:

The method that can increase the amount of AgCls produced is to be identified.

Concept Introduction:

The limiting reagent of a reaction is that reactant of the reaction that controls the amount of product formed. The limiting reagents limits the amount of product and by adding some more amount of the limiting reagent in the reaction mixture, the amount of product can be increased.

The molarity of a solution is defined as the number of mole of solute dissolved in one liter of the solution. The formula for molarity is given as:

M=nV

Where,

• n represents the number of moles of the solute.
• V represents the volume of the solution.
Explanation

Reason for correct option:

(b) The volume of 3.0MAgNO3aq is 1L.

The volume of 1MCuCl2aq is 1L.

The molarity of a solution is given as:

M=nV

Where,

• n represents the number of moles of the solute.
• V represents the volume of the solution.

Rearrange the above equation for the value of n.

n=MV    (1)

Substitute the value of volume and molarity of CuCl2aq in the equation (1).

n=1.0M1.0L1molL11M=1.0mol

The number of moles of CuCl2aq involved in the reaction is 1.0mol.

Substitute the value of volume and molarity of AgNO3aq in the equation (1).

n=3.0M1.0L1molL11M=3.0mol

The number of moles of AgNO3aq involved in the reaction is 3.0mol

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