   Chapter 15.4, Problem 15.5SC ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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# ercise 15.5 Calculate the number of moles of Cl ions in 1.75 L of 1.0 X 10 M AICl3.

Interpretation Introduction

Interpretation:

The number of moles of Cl- ions in 1.75 L of 1.0×103M

AlCl3 should be calculated.

Concept Introduction:

Molarity of the solution is equal to the ratio of number of moles of solute to the volume of solution in litres.

The mathematical expression is given by:

Molarity = number of moles of solute volume of solution in litres

Number of moles = given massmolar mass.

Explanation

Given information:

Volume of solution = 1.75 L

Molarity of aluminium chloride = 1.0×103M

When aluminium chloride in solid form dissolves in water, following reaction takes place:

AlCl3(s)H2O(l)Al3+(aq)+3Cl(aq)

According to the reaction, aluminium chloride breaks down into one mole of aluminium ion and three moles of chloride ion.

Thus, in 1.0×103M of aluminium chloride solution, the concentration of aluminium ion = 1×1.0×103M = 1

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