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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

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BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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74. What Volume of 0.101 M HNO3 is required to neutralize each of the following solutions?

a. 12.7 mL of 0.501 M NaOH

b. 24.9 mL of 0.00491 M Ba(OH)2

c. 49.1 mL of 0.103 MNH3

d. 1.21 L of 0.102 MKOH

Interpretation Introduction

(a)

Interpretation:

The volume of 0.101M

HNO3 required to neutralize the given solution is to be calculated.

12.7mL of 0.501M

NaOH.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

Moles=MassgMolarmass

The molarity is calculated by the formula,

Molarity=NumberofmolesofsoluteVolumeofsolution.

Explanation

The value of M1, V1 and M2 is given to be 0.501M, 12.7mL and 0.101M respectively. V2 is the volume which is required to neutralize the given reaction.

The balanced equation when HNO3 reacts with NaOH is shown below.

NaOH+HNO3H2O+NaNO3

The above reaction indicates that one equivalent of HNO3 required to neutralize one equivalent of NaOH.

The relationship between concentration and volume of NaOH and HNO3 solutions is shown below.

M1V1=M2V2

Where,

  • M1 is the molarity of NaOH solution.
  • V1 is the volume of NaOH solution
Interpretation Introduction

(b)

Interpretation:

The volume of 0.101M

HNO3 required to neutralize the given solution is to be calculated.

24.9mL of 0.00491M

BaOH2.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

Moles=MassgMolarmass

The molarity is calculated by the formula,

Molarity=NumberofmolesofsoluteVolumeofsolution.

Interpretation Introduction

(c)

Interpretation:

The volume of 0.101M

HNO3 required to neutralize the given solution is to be calculated.

49.1mL of 0.103M

NH3.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

Moles=MassgMolarmass

The molarity is calculated by the formula,

Molarity=NumberofmolesofsoluteVolumeofsolution.

Interpretation Introduction

(d)

Interpretation:

The volume of 0.101M

HNO3 required to neutralize the given solution is to be calculated.

1.21L of 0.102M

KOH.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

Moles=MassgMolarmass

The molarity is calculated by the formula,

Molarity=NumberofmolesofsoluteVolumeofsolution.

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