EBK ORGANIC CHEMISTRY
6th Edition
ISBN: 8220103151757
Author: LOUDON
Publisher: MAC HIGHER
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Chapter 21, Problem 21.8P
Interpretation Introduction
Interpretation:
The structure of a compound with the molecular formula
Concept introduction:
Many nuclei and electrons have spin. Due to this spin magnetic moment arises. The energy of this magnetic moment depends on the orientation of the applied magnetic field. In NMR spectroscopy, every nucleus has a spin. There is an
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Predict the structure of a compound based on this 13C NMR spectra. The chemical formula of this compound is C4H6O2. Briefly explain your answer.
The two compounds 1,2-dibromobenzene and 1 3-dibromobenzene both have the molecular formula C6H4Brz.
a)Draw the chemical structures of the two molecules.
b)Can these two molecules be distinguished by 1H NMR spectroscopy?
Give reasons for your answer and describe the number of proton environments and their splitting for both molecules.
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Can these two molecules be distinguished by IR spectroscopy? Give reasons for your answer and describe the main IR signals (with frequencies) you expect to see for both molecules.
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Based on this IR spectrum and 1H NMR spectrum and the given chemical formula is C9H10O2, what would be the chemical structure of the compound? Please give a full analysis of the NMR spectra for given compound.
Chapter 21 Solutions
EBK ORGANIC CHEMISTRY
Ch. 21 - Prob. 21.1PCh. 21 - Prob. 21.2PCh. 21 - Prob. 21.3PCh. 21 - Prob. 21.4PCh. 21 - Prob. 21.5PCh. 21 - Prob. 21.6PCh. 21 - Prob. 21.7PCh. 21 - Prob. 21.8PCh. 21 - Prob. 21.9PCh. 21 - Prob. 21.10P
Ch. 21 - Prob. 21.11PCh. 21 - Prob. 21.12PCh. 21 - Prob. 21.13PCh. 21 - Prob. 21.14PCh. 21 - Prob. 21.15PCh. 21 - Prob. 21.16PCh. 21 - Prob. 21.17PCh. 21 - Prob. 21.18PCh. 21 - Prob. 21.19PCh. 21 - Prob. 21.20PCh. 21 - Prob. 21.21PCh. 21 - Prob. 21.22PCh. 21 - Prob. 21.23PCh. 21 - Prob. 21.24PCh. 21 - Prob. 21.25PCh. 21 - Prob. 21.26PCh. 21 - Prob. 21.27PCh. 21 - Prob. 21.28PCh. 21 - Prob. 21.29PCh. 21 - Prob. 21.30PCh. 21 - Prob. 21.31PCh. 21 - Prob. 21.32APCh. 21 - Prob. 21.33APCh. 21 - Prob. 21.34APCh. 21 - Prob. 21.35APCh. 21 - Prob. 21.36APCh. 21 - Prob. 21.37APCh. 21 - Prob. 21.38APCh. 21 - Prob. 21.39APCh. 21 - Prob. 21.40APCh. 21 - Prob. 21.41APCh. 21 - Prob. 21.42APCh. 21 - Prob. 21.43APCh. 21 - Prob. 21.44APCh. 21 - Prob. 21.45APCh. 21 - Prob. 21.46APCh. 21 - Prob. 21.47APCh. 21 - Prob. 21.48APCh. 21 - Prob. 21.49APCh. 21 - Prob. 21.50APCh. 21 - Prob. 21.52APCh. 21 - Prob. 21.53APCh. 21 - Prob. 21.54APCh. 21 - Prob. 21.55APCh. 21 - Prob. 21.56APCh. 21 - Prob. 21.57APCh. 21 - Prob. 21.58APCh. 21 - Prob. 21.59APCh. 21 - Prob. 21.60APCh. 21 - Prob. 21.61APCh. 21 - Prob. 21.62APCh. 21 - Prob. 21.63AP
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- Sketch the 1H NMR spectra of the following compounds.arrow_forwardAnalyze the 13C-NMR spectrum of C8H9NO given below and draw the structure of the compound.arrow_forwardAccount for the following observations: (a) The 1H NMR spectrum of cyclohexane shows a single peak at room temperature, but when the temperate is lowered significantly the peak starts to broaden and then separates into two. (b) At room temperature, the 19F NMR spectrum of PF5 shows two lines, and even at the lowest experimentally accessible temperatures the spectrum is substantially unchanged. (c) In the 1H NMR spectrum of a casually prepared sample of ethanol a triplet and a quartet are seen. These multiplets show additional splittings if the sample is prepared with the careful exclusion of water.arrow_forward
- The H1H1 NMR spectrum shown corresponds to an unknown compound with the molecular formula C6H10C6H10. There are no strong IR bands between 2100 and 2300 or 3250 and 3350 cm−1. Deduce and draw the structure of the molecule that corresponds to the spectrum.arrow_forwardThe functional groups in an organic compound can frequently be deduced from its infrared absorption spectrum. A compound containing no nitrogen exhibits strong, broad absorption across the 2500-3300 cm³¹ region, accompanied by 2200 (w) and 1715 (s) cm-¹ bands. Relative absorption intensity: (s)=strong, (m)=medium, (w)=weak. What functional class(es) does the compound belong to? List only classes for which evidence is given here. Attach no significance to evidence not cited explicitly. Do not over-interpret exact absorption band positions. None of your inferences should depend on small differences like 10 to 20 cm³¹. The functional class(es) of this compound is(are) . (Enter letters from the table below, in any order, with no spaces or commas.) a. alkane (List only if no other functional class applies.) b. alkene c. terminal alkyne d. internal alkyne e. arene f. alcohol g. ether h. amine i. aldehyde or ketone j.carboxylic acid k. ester I. nitrilearrow_forwardAnalysis of a sweet-smelling, neutral compound of carbon, hydrogen and oxygen produced the following results: %C = 54.5; %H = 9.1. From its mass spectrum, the molecular ion had a mass/charge ratio of 88. Its infra-red spectrum showed a prominent peak at 1735 cm–1. Figure below shows the NMR spectrum of the compound. Suggest a structural Formula for this compound.arrow_forward
- The 1H-NMR spectrum of compound B,C7H14O , consists of the following signals: δ 0.9 (t, 6H), 1.6 (sextet, 4H), and 2.4 (t, 4H). Draw the structural formula of compound B.arrow_forwardThe functional groups in an organic compound can frequently be deduced from its infrared absorption spectrum. A compound containing no nitrogen exhibits strong, broad absorption across the 2500-3300 cm-1 region, accompanied by 2200 (w) and 1715 (s) cm-1bands.Relative absorption intensity: (s)=strong, (m)=medium, (w)=weak. What functional class(es) does the compound belong to? List only classes for which evidence is given here. Attach no significance to evidence not cited explicitly.Do not over-interpret exact absorption band positions. None of your inferences should depend on small differences like 10 to 20 cm-1. The functional class(es) of this compound is(are)fill in the blank 1.(Enter letters from the table below, in any order, with no spaces or commas.) a. alkane (List only if no other functional class applies.) b. alkene h. amine c. terminal alkyne i. aldehyde or ketone d. internal alkyne j. carboxylic acid e. arene k. ester f. alcohol l. nitrile g. etherarrow_forwardFollowing are the 13C and 1H spectra for one of four isomeric bromoalkanes with formula C4H9Br. Assign a structure of the isomer.arrow_forward
- 3. Which of the following isotopes are NMR active and explain the reason: ¹H,2H, ¹2C, ¹³C, 14N, 15H, 180. What are the three major information that ¹H NMR provides? Discuss how the information can be used to determine the structure of organic molecules.arrow_forwardWhat is the NMR Spectra for C6H10O2 and what is the chemical formula for the compund?arrow_forwardSuggest structures given the 1H NMR spectra and formulas for each of the compounds below. C4H10Oarrow_forward
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NMR Spectroscopy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=SBir5wUS3Bo;License: Standard YouTube License, CC-BY