(a)
Interpretation:
Theaverage Benzene concentration
Concept introduction:
The ideal gas equation is represented as follows:
Here,
(b)
Interpretation:
The Time-Weighted Average Exposure (TWA) of the worker needs to be determined.
Concept introduction:
The workers TWA
(c)
Interpretation:
The actions taken by the company to ensure that the workers get expose to the chemical in the recommended limits needs to be determined.
Concept introduction:
NIOSH means TheNational Institute for Occupational Safety and Health, OSHA means the Federal Occupational Safety and Health Administration.
NIOSH is an education and research institution while OSHA generates and applies regulations, NIOSH focuses on the safety in theoccupational scientific field.
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Chapter 5 Solutions
EBK ELEMENTARY PRINCIPLES OF CHEMICAL P
- Ozone is a trace atmospheric gas which plays an important role in screening the Earth from harmful ultraviolet radiation, and the abundance of ozone is commonly reported in Dobson units. Imagine a column passing up through the atmosphere. The total amount of O3 in the column divided by its cross-sectional area is reported in Dobson units with 1 Du = 0.4462 mmol m−2. What amount of O3 (in moles) is found in a column of atmosphere with a cross-sectional area of 1.00 dm2 if the abundance is 250 Dobson units (a typical midlatitude value)? In the seasonal Antarctic ozone hole, the column abundance drops below 100 Dobson units; how many moles of O3 are found in such a column of air above a 1.00 dm2 area? Most atmospheric ozone is found between 10 and 50 km above the surface of the Earth. If that ozone is spread uniformly through this portion of the atmosphere, what is the average molar concentration corresponding to (a) 250 Dobson units, (b) 100 Dobson units?arrow_forward(a) What is the difference between chlorofluorocarbonsand hydrofluorocarbons? (b) Why are hydrofluorocarbonspotentially less harmful to the ozone layer than CFCs?arrow_forwardTime Left:0:55:00 A student completes the experiment The Universal Gas Constant and obtains the following data for one trial. mass of magnesium (g): Initial gas volume (ml): Final Volume (mL): Temperature (°C): Atmospheric pressure (inHg): Ah (cm of water): F3 80 모 Calculate the partial pressure of hydrogen, PH2, for this trial. Give your answer in torr (mmHg). 1 in Hg = 25.4 mmHg 1 cm water = 0.735559 mmHg 1 mol Mg = 24.305 g Mg TABLE D-4 TEMP 1_DEG₁_C_1 1 3 I 1 1 Q F4 0 1 = 2 3 4 5 6 7 8 10 11 12 13 14 0.0 0.1 0.0326 0.00 35.30 21.3 30.21 16 17.13 F5 6.100 | 6.143 1 6.544 1 6.589 0.2 1 VAPOR PRESSURE OF HATER 0-30 DEG. C IN MM HG 1 4.579 4.612 4.646 | 4.924 | 4.959 4.995 15.291 4.660 4.714 5.0315.068 5.329 5.367 5.406 5.445 4.7484.783 4.818 5.104 | 5.141 | 5.178 5.484 5.523 5.563 5.888 5.930 6.230 16.274 6.318 5.363 15.683 15.723 | 5.764 | 5.8051 5.146 6.186 6.636 5.972 1 6.0141 6.057 1 6.407 1 6.453 6.498 1 6.82 | 6.729 6.776 6.823 | 6.871 | 6.919 | 6.967 1 T T 1 I T I 1 17.0167,064…arrow_forward
- Chemistry and Environmental Pollution Using suitable examples, discuss the chemical, biological, and physicalreactivity processes of contaminants.arrow_forwardWrite the balanced chemical equation of the reaction in your solutions sheet. What is the sum of all the coefficients of the balanced chemical equation? Determine the pressure of the trapped gas inside the eudiometer in mmHg. Determine the partial pressure of the collected CO2 in mm Hg. How many millimoles of CO2 was collected? What is the %purity of the sample to the nearest whole number (disregard the % symbol)?arrow_forwardA commercial 737 jet transporting 143 passengers and 5 crew members from Kansas city (MCI) to Baltimore (BWI) burned 11800 lb. of Jet A fuel. Jet A fuel is kerosene based, consisting primarily of CnH2n+2 hydrocarbons, with n = 6 to 16, so the Carbon:Hydrogen ratio is close to 1:2. During this flight How much CO2 would be released into the atmosphere if those passengers and crew made the trip instead, in pairs, in hybrid cars at 50 miles per gallon. (Assume the density of gasoline to be 0.75kg L-1 and that carbon and hydrogen dominate the composition in a ratio 1:2. The road trip is 1082 miles.arrow_forward
- The studies on the toxic effects of chemicals in the environment are important in attempting to measure and assess the toxic effects. (a)With a suitable examples, identify TWO main effects of toxicity. ( 4 ) (b)There are several routes of entry of the toxicant into the human body which in the end can cause harmful diseases. From your point of view, why a modern lifestyle can create a pattern of harmful disease due to a toxicant and suggest how to overcome the unwanted interaction from happening. ( 16 ) ( Total / Jumlah: 20 )arrow_forward段階的に解決し、 人工知能を使用せず、 優れた仕事を行います ご支援ありがとうございました SOLVE STEP BY STEP IN DIGITAL FORMAT DON'T USE AI | DON'T USE AI | DON'T USE AI | DON'T USE AI | 6. The depletion of ozone (O_3) in the stratosphere has been a topic of great concern among scientists in recent years. It is believed that ozone can react with nitric oxide (NO) that comes from aircraft emissions at high altitudes. The reaction is 03 + NO → O2 + NO₂ If 0.740 g of Os reacts with 0.670 g of NO, how many grams of NO_2 will be produced? Which compound is the limiting reactant? Calculate the mass of the excess reactant that is recovered by finish the reaction.arrow_forwardCalculate the total mass (in kg) of nitrogen, oxygen, and carbon dioxide gases in the atmosphere. Assume that the total mass of air in the atmosphere is 5.25 x 1021 g. Mass of N2 x 10 kg Mass of O2 x 10 |kg Mass of CO2 x 10 kg (Enter your answers in scientific notation.) Composition of dry air at sea level Composition (% by Volume) Gas N2 78.03 O2 20.99 Ar 0.94 CO2 0.033 Ne 0.0015 Не 0.000524 Kr 0.00014 Хе 0.000006arrow_forward
- Given the Volumetric Analysis of a Natural Gas: CH4 = 67.3% Nitrogen = 9.6% O2 = 2.7% CO = 0.8% C2H6 = 15.4% CO2 = 1.8% H2 = 2.4% Calculate the A/F ratio by mass considering CO = 6.1% CO2. Note: Use four (4) decimal places in your solution and answer.arrow_forwardUse the figure below (Figure F01-7-8) to answer this question. Temperature Anomaly (°C) 106 [OSS [ [(4 10% COD -€62 · [(14) -€0.06 Annual mean 15 year mean 1:00:3 130233 1840) Which statement is a correct interpretation of the data depicted in the plot? The mean global temperature has decreased by ~0.9 °C since 1880. O The mean global temperature has increased by ~0.9 °C since 1880. O The mean global temperature has increased by ~1.1 °C since 1880. The mean global temperature has decreased by ~1.1 °C since 1880. The mean global temperature has increased and decreased since 1880 but overall, the temperature has remained constant.arrow_forwardExplain the relation between air pollution and environmental chemistry.arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
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