Chapter 5, Problem 5.38P

Interpretation Introduction

(a)

Interpretation:

The rate of mass lost through the breathing process $\text{kg/day}$ and the volume of water in liters that needs to be drink per day to overcome the water lost in respiration needs to be determined.

Concept introduction:

Mole fraction is defined as the ratio of moles of one component to total moles of the mixture.

$x_A=\frac{n_A}{n_A+n_B}$

Here $x_A$ is the mole fraction, $n_{A}and{n}_B$ are moles of $A\&B$ respectively.

Interpretation Introduction

(b)

Interpretation:

The rate of mass lost $\left(\frac{\text{g}}{\text{day}}\right)$ through breathing and water that needs to be drink $\left(\frac{\text{L}}{\text{day}}\right)$ needs to be determined.

Concept introduction:

:Mole fraction is defined as the ratio of moles of one component to total moles of the mixture.

$x_A=\frac{n_A}{n_A+n_B}$

Here $x_A$ is the mole fraction, $n_{A}and{n}_B$ are moles of $A\&B$ respectively.

Mass of any substance $\left(m\right)$ can be calculated from Number of Moles $\left(n\right)$ and Molecular Weight $\left(M_{wt}\right)$.

$m=n\times M_{wt}$

Interpretation Introduction

(c)

Interpretation:

The effects needs to be determined.

Concept introduction:

The ideal gas equation of state is given as follows:

$\begin{array}{l}P\dot{V}=\dot{n}RT\\ \dot{n}=\frac{P\dot{V}}{RT}\end{array}$

Mole fraction is defined as the ratio of moles of one component to total moles of the mixture.

$x_A=\frac{n_A}{n_A+n_B}$

Here $x_A$ is the mole fraction, $n_{A}and{n}_B$ are moles of $\text{A\&B}$ respectively.