(a)
To find: The equation of tangent to the given curve that is parallel to the line
(a)
Explanation of Solution
Given: The given equation curve is
Differentiate the equation of curve.
Consider the equation of line.
Substitute
Since the line are parallel so there slope will be equal.
Therefore, the equation of tangent parallel to the given curve is
(b)
To find: The equation of tangent to the given curve that passes through the origin
(b)
Explanation of Solution
Given: The given equation curve is
Let assume that the tangent at
Differentiate the equation of curve.
Slope at
The equation of tangent is calculated as,
The tangent will pass through the origin ig
Thus,
Therefore, the equation of tangentpassing through the origin of the given curve is
Chapter 3 Solutions
Single Variable Calculus: Concepts and Contexts, Enhanced Edition
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning