# The equation of the tangent line to the curve at the given point ### Single Variable Calculus: Concepts...

4th Edition
James Stewart
Publisher: Cengage Learning
ISBN: 9781337687805 ### Single Variable Calculus: Concepts...

4th Edition
James Stewart
Publisher: Cengage Learning
ISBN: 9781337687805

#### Solutions

Chapter 3.1, Problem 28E
To determine

## To find:The equation of the tangent line to the curve at the given point

Expert Solution

The equation of the tangent line is y=(4x3+4x1)(x2)+2

### Explanation of Solution

Given:

The function is

f(x)=x4+2x2x

Concept used:

An equation of a line l through a point P1(x1,y1) with slope m . If P(x,y) is any point with xx1

Then P is on l if and only if the slope of the line through P1 and P

The equation is yy1=m(xx1)

Calculation:

The function

f(x)=x4+2x2x...................(1)

The derivative of a function

y=f(x)y=f(x)=dydx

Differentiating the equation (1) with respect to x

dydx=ddx(x4+2x2x)dydx=4x3+4x1

The point is (1,2)

The equation is

yy1=m(xx1)y2=(4x3+4x1)(x2)y=(4x3+4x1)(x2)+2

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