To find:
The equation of the tangent and parallel to the line
Answer to Problem 54E
The equation of the both line is
Explanation of Solution
Given:
The tangent to the curve
Parallel to the line
Concept used:
The equation is in slope −intercept form,
An equation for the line through the point
Calculation:
The function
The derivative of a function
Differentiating the equation (1) with respect to
The derivative is slope of the tangent line so in order to the slope of the tangent line
The derivative of constant is zero
The equation is in slope −intercept form
The slope of the line is
From equation (2) and equation (3)
The coordinates of points
An equation for the line through the point
Draw the table
Test one point in each of the region formed by the graph
If the point satisfies the function then shade the entire region to denote that every point in the region satisfies the function
| | | | |
| | | | |
Chapter 3 Solutions
Single Variable Calculus: Concepts and Contexts, Enhanced Edition
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning