# The differentiation of the given function

### Single Variable Calculus: Concepts...

4th Edition
James Stewart
Publisher: Cengage Learning
ISBN: 9781337687805

### Single Variable Calculus: Concepts...

4th Edition
James Stewart
Publisher: Cengage Learning
ISBN: 9781337687805

#### Solutions

Chapter 3.1, Problem 18E
To determine

## To find:The differentiation of the given function

Expert Solution

Differentiating the function is dydx=x(2x3)2(x23x+1)(x3)

### Explanation of Solution

Given:

The function is

f(x)=x23x+1x2

Concept used:

Definition of the differentiation:-Differentiation is the action of computing a derivative

The derivative of a function y=f(x) of a variable x is a measure of the rate at which the value y of the function changes with respect to x

Calculation:

The function

f(x)=x23x+1x2...................(1)

The derivative of a function

y=f(x)y=f(x)=dydx

Differentiating the equation (1) with respect to x

dydx=ddx(x23x+1x2)dydx=x2ddx(x23x+1)(x23x+1)ddxx2(x2)2dydx=x2(2x3)(x23x+1)(2x)(x4)dydx=x{x(2x3)(x23x+1)(2)}(x4)dydx=x(2x3)2(x23x+1)(x3)

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