   Chapter 16, Problem 69AP

Chapter
Section
Textbook Problem

Capacitors C1 = 6.0 μF and C2 = 2.0 μF are charged as a parallel combination across a 250-V battery. The capacitors are disconnected from the battery and from each other. They are then connected positive plate to negative plate and negative plate to positive plate. Calculate the resulting charge on each capacitor.

To determine
The resulting charge on each capacitor.

Explanation

Given info: The capacitors C1=6.0μF and C2=2.0μF are connected in parallel combination to a 250 V battery, The capacitors C1=6.0μF and C2=2.0μF are connected in parallel combination to a 250 V battery.

Explanation:

The net charge is,

Q=(C1C2)(ΔV)

Substitute 6.0μF for C1 , 2.0μF for C2 and 250 V for ΔV

Q=(6.0μF2.0μF)(250V)=1.00×103μC

Formula to calculate the charge on C1 is,

Q1=(C1C1+C2)Q

Substitute 6.0μF for C1 , 2.0μF for C2 and 1

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