   Chapter 16.10, Problem 2.1ACP

Chapter
Section
Textbook Problem

Convert the pK values to K values for the ionization of HCl, HClO4, and H2SO4 in glacial acetic acid. Rank these acids in order from strongest to weakest.

Interpretation Introduction

Interpretation: The pK values has to be converted to K values for the ionization of HCl, HClO4 and H2SO4. The order of these acids from strongest to weakest has to be ranked

Concept introduction:

Acid dissociation constant Ka represents how strong the acid is in a solution.

pKa=logKa

The strength of acid increases as the value of Ka increases

Explanation
• The pK a value of HCl_ is 6.8

Hence, Ka value is calculated as:

pKa=logKa8.8=logKalogKa=8.8Ka=1.58×109

The Ka value of HCl is 1.58×109

• The pK a value of HClO4_ is 5.3

Hence, Ka value is calculated as:

pKa=logKa5.3=logKalogKa=5.3Ka=5

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