   Chapter 16, Problem 16PS

Chapter
Section
Textbook Problem

Write an equilibrium constant expression for the reaction of fluoride ion, a weak base, with water.

Interpretation Introduction

Interpretation: The equilibrium constant expression for the reaction of Flouride ion with water has to be written.

Concept introduction: An equilibrium constant (K) is the ratio of concentration of products and reactants raised to appropriate stoichiometric coefficient at equlibrium.

For the general base B,

B(aq)+H2O(l)BH(aq)+OH(aq)

The relative strength of an acid and base in water can be also expressed quantitatively with an equilibrium constant as follows:

Kb=[BH][OH][B] (1)

An equilibrium constant (K) with subscript b indicate that it is an equilibrium constant of base in water.

Explanation

The reaction of Flouride ion with water as follows:

F(aq)+H2O(l)HF(aq)+OH(aq)

Flouride ion is a weak base because it proceduces HF which is a strong acid since flouride ion is a weak base

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