Chapter 4, Problem 127IL

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# Chromium(III) chloride forms many compounds with ammonia. To find the formula of one of these compounds, you titrate the NH3 in the compound with standardized acid.Cr(NH3)xCl3(aq) + x HCl(aq) → x NH4+(aq) + Cr3+(aq) + (x + 3) Cl−(aq)Assume that 24.26 mL of 1.500 M HCl is used to titrate 1.580 g of Cr(NH3)xCl3. What is the value of x?

Interpretation Introduction

Interpretation:

The value of x in the compound Cr(NH3)xCl3 involved in the given reaction has to be determined.

Concept introduction:

• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
• Stoichiometric factor is a relationship between reactant and product which is obtained from the balanced chemical equation for a particular reaction.

Concentrationofsubstance=Amountof substancevolumeofthesubstance

Explanation

Balanced chemical equation for the given reaction is,

â€‚Â Cr(NH3)xCl3(aq)â€‰â€‰+â€‰xHCl(aq)â€‰â†’â€‰xâ€‰NH4+(aq)â€‰+â€‰Cr(aq)3+â€‰+â€‰(x+3)â€‰Cl(aq)âˆ’

Amount of HCl can be calculated from its volume and concentration as follows,

â€‚Â Amountâ€‰ofâ€‰HCl =â€‰CHClâ€‰Ã—â€‰VHCl =â€‰1.500â€‰molLâ€‰Ã—â€‰0.02426â€‰L =â€‰0.3639â€‰â€‰molâ€‰HCl

Molar mass of Cr(NH3)xCl3 can be calculated as,

â€‚Â 58.93â€‰+â€‰(14.01+1.008Ã—3)xâ€‰â€‰+35.45â€‰Ã—3=â€‰â€‰17.034xâ€‰+â€‰â€‰165.28

Cr(NH3)xCl3 And Â HCl are in stoichiometric ratio

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