BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Solutions

Chapter
Section
BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

The reaction of 750. g each of NH3 and O2 was found to produce 562 g of NO (see pages 177-179).

4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(l)

(a) What mass of water is produced by this reaction?

(b) What mass of O2 is required to consume 750. g of NH3?

(a)

Interpretation Introduction

Interpretation:

The mass of water produced and the mass of oxygen require to react with 750.0ofNH3 in the given reaction should be determined.

Concept introduction:

  Numberofmole=GivenmassofthesubstanceMolarmass

  • The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
  • For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
  • Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
  • Stoichiometric factor is a relationship between reactant and product which is obtained from the balanced chemical equation for a particular reaction.
  • Limiting reagent: limiting reagent is a reactant, which consumes completely in the chemical reaction. The quantity of the product depends on this limiting reagent, it can be determined with the help of balanced chemical equation for the reaction.
Explanation

The balanced chemical reaction equation for the given reaction is,

  4NH3(g)+5O2(g)4NO(g)+6H2O(l)

The amount (moles) of NH3andO2  available can be calculated by using the equation

  Numberofmole=GivenmassofthesubstanceMolarmass

  Amount of   NH3 = 750.0gNH3×1molNH317gNH3 = 44.1molNH3

  Amount of O2 =750gO2×1molO232gO2 =23

(b)

Interpretation Introduction

Interpretation:

The mass of O2 required to consume 750.0g of NH3 has to be determined.

Concept introduction:

  Numberofmole=GivenmassofthesubstanceMolarmass

  • The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
  • For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
  • Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
  • Stoichiometric factor is a relationship between reactant and product which is obtained from the balanced chemical equation for a particular reaction.
  • Limiting reagent: limiting reagent is a reactant, which consumes completely in the chemical reaction. The quantity of the product depends on this limiting reagent, it can be determined with the help of balanced chemical equation for the reaction.

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started
Sect-4.8 P-4.11CYUSect-4.8 P-4.12CYUSect-4.8 P-4.13CYUSect-4.9 P-4.14CYUSect-4.9 P-1.1ACPSect-4.9 P-2.1ACPSect-4.9 P-3.1ACPSect-4.9 P-4.1ACPSect-4.9 P-4.2ACPSect-4.9 P-4.3ACPSect-4.9 P-4.4ACPCh-4 P-1PSCh-4 P-2PSCh-4 P-3PSCh-4 P-4PSCh-4 P-5PSCh-4 P-6PSCh-4 P-7PSCh-4 P-8PSCh-4 P-9PSCh-4 P-10PSCh-4 P-11PSCh-4 P-12PSCh-4 P-13PSCh-4 P-14PSCh-4 P-15PSCh-4 P-16PSCh-4 P-17PSCh-4 P-18PSCh-4 P-19PSCh-4 P-20PSCh-4 P-21PSCh-4 P-22PSCh-4 P-23PSCh-4 P-24PSCh-4 P-25PSCh-4 P-26PSCh-4 P-27PSCh-4 P-28PSCh-4 P-29PSCh-4 P-30PSCh-4 P-31PSCh-4 P-32PSCh-4 P-33PSCh-4 P-34PSCh-4 P-35PSCh-4 P-36PSCh-4 P-37PSCh-4 P-38PSCh-4 P-39PSCh-4 P-40PSCh-4 P-41PSCh-4 P-42PSCh-4 P-43PSCh-4 P-44PSCh-4 P-45PSCh-4 P-46PSCh-4 P-47PSCh-4 P-48PSCh-4 P-49PSCh-4 P-50PSCh-4 P-51PSCh-4 P-52PSCh-4 P-53PSCh-4 P-54PSCh-4 P-55PSCh-4 P-56PSCh-4 P-57PSCh-4 P-58PSCh-4 P-59PSCh-4 P-60PSCh-4 P-61PSCh-4 P-62PSCh-4 P-63PSCh-4 P-64PSCh-4 P-65PSCh-4 P-66PSCh-4 P-67PSCh-4 P-68PSCh-4 P-69PSCh-4 P-70PSCh-4 P-71PSCh-4 P-72PSCh-4 P-73PSCh-4 P-74PSCh-4 P-75PSCh-4 P-76PSCh-4 P-77PSCh-4 P-79GQCh-4 P-80GQCh-4 P-81GQCh-4 P-82GQCh-4 P-83GQCh-4 P-84GQCh-4 P-85GQCh-4 P-86GQCh-4 P-87GQCh-4 P-88GQCh-4 P-89GQCh-4 P-90GQCh-4 P-91GQCh-4 P-92GQCh-4 P-93GQCh-4 P-94GQCh-4 P-95GQCh-4 P-96GQCh-4 P-97GQCh-4 P-98GQCh-4 P-99GQCh-4 P-100GQCh-4 P-101GQCh-4 P-102GQCh-4 P-103GQCh-4 P-104GQCh-4 P-105GQCh-4 P-106GQCh-4 P-107GQCh-4 P-108GQCh-4 P-109GQCh-4 P-110GQCh-4 P-111GQCh-4 P-112GQCh-4 P-113GQCh-4 P-115GQCh-4 P-116GQCh-4 P-117GQCh-4 P-118GQCh-4 P-119GQCh-4 P-120GQCh-4 P-121ILCh-4 P-122ILCh-4 P-123ILCh-4 P-125ILCh-4 P-126ILCh-4 P-127ILCh-4 P-128ILCh-4 P-129ILCh-4 P-130ILCh-4 P-135SCQCh-4 P-136SCQCh-4 P-137SCQCh-4 P-139SCQCh-4 P-141SCQCh-4 P-142SCQ

Additional Science Solutions

Find more solutions based on key concepts

Show solutions add

Platinum has a density of 21.4 g/cm3. What is the mass of 5.9 cm3 of this metal?

General Chemistry - Standalone book (MindTap Course List)

Body fat can be assessed by which of the following techniques? a. blood lipid test b. chest circumference c. du...

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

What is meant by biological evolution?

Human Biology (MindTap Course List)

What is hereditarianism, and what is the invalid assumption it makes?

Human Heredity: Principles and Issues (MindTap Course List)

If Earth did not rotate, could you still define the ecliptic? Why or why not?

Horizons: Exploring the Universe (MindTap Course List)

(a) What is the minimum speed, relative to the Sun, necessary for a spacecraft to escape the solar system if it...

Physics for Scientists and Engineers, Technology Update (No access codes included)