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Chapter 4, Problem 85GQ
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### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

#### Solutions

Chapter
Section
BuyFindarrow_forward

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# Sodium azide, an explosive chemical used in auto-mobile airbags, is made by the following reaction:NaNO3 + 3 NaNH2 → NaN3 + 3 NaOH + NH3If you combine 15.0 g of NaNO3 with 15.0 g of NaNH2, what mass of NaN3 is produced?

Interpretation Introduction

Interpretation:

The mass of NaN3 produced in the given reaction has to be determined.

Concept introduction:

Numberofmole=GivenmassofthesubstanceMolarmass

• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
• Stoichiometric factor is a relationship between reactant and product which is obtained from the balanced chemical equation for a particular reaction.
• Limiting reagent: limiting reagent is a reactant, which consumes completely in the chemical reaction. The quantity of the product depends on this limiting reagent, it can be determined with the help of balanced chemical equation for the reaction.
Explanation

The balanced chemical reaction equation for the given reaction is,

â€‚Â NaNO3â€‰+3â€‰NaNH2â€‰â†’â€‰NaN3â€‰+3â€‰NaOH+â€‰NH3

The amount (moles) of NaNO3â€‰â€‰andâ€‰â€‰NaNH2 available can be calculated by using the equation.

â€‚Â Numberâ€‰ofâ€‰moleâ€‰=Givenâ€‰massâ€‰ofâ€‰theâ€‰substanceMolarâ€‰massâ€‰

AmountÂ ofÂ Â Â NaNO3 Â  =Â 15.0â€‰gâ€‰NaNO3â€‰Ã—1â€‰molâ€‰NaNO385â€‰gâ€‰NaNO3 =Â Â 0.176â€‰molâ€‰NaNO3AmountÂ ofÂ Â NaNH2 =Â 15â€‰gâ€‰NaNH2Ã—1â€‰â€‰molâ€‰NaNH239.01â€‰gâ€‰NaNH2 =Â 0

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