Chapter 9, Problem 3CR

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

Chapter
Section

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
1 views

ow do we know that 16.00 g of oxygen Contains the same number of atoms as does 12.01 g of carbon, and that 22.99 g of sodium contains the same number of atoms as each of these? How do we know that 106.0 g of Na 2 CO 3 contains the same number of carbon atoms as does 12.01 g of carbon, hut three times as many oxygen atoms as in 16.00 g of oxygen, and twice as many sodium atoms as in 22.99 g of sodium?

Interpretation Introduction

Interpretation:

To describe how 16.00 g oxygen, 12.01 g carbon and 22.999 g of sodium contains the same number of atoms.

How the 106.0 g of Na2CO3 contains the same number of carbon atoms as does 12.01 g carbon but three times as many oxygen atoms in 16.00 g of oxygen and twice as many sodium atoms as in 22.99 g of sodium should be described?

Concept Introduction:

The molar mass of any element is the mass of 6.02×1023 atoms or 1 mole of that element. The unit of molar mass is grams.

Mass of any substance can be calculated as follows:

Mass in gram = Number of moles×Molar mass

Number of moles of any substance can be calculated as follows:

Number of moles = Amount in grams Molar mass.

Explanation

Number of moles = Amount in grams Molar mass

First calculate the number of moles of all as follows:

16.00 g ONumber of moles = Amount in grams Molar massNumber of moles = 16.00 g O 16.00 g /mole=1.00 mole O

12.01 g CNumber of moles = Amount in grams Molar massNumber of moles = 12.01 g C 12.01 g /mole=1

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