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A favorite demonstration among chemistry instructors, to show that the properties of a compound differ from those of its constituent elements, involves iron filings and powdered sulfur. If the instructor takes samples of iron and sulfur and just mixes them together, the two elements can be separated from one another with a magnet (iron is attracted (o a magnet, sulfur is not). If the instructor then combines and heats the mixture of iron and sulfur, a reaction takes place and the elements combine to form iron (II) sulfide (which is not attracted by a magnet). :math> Fe ( s ) + S ( s ) → FeS ( s ) ppose 5.25 g of iron filings is combined with 12.7 g of sulfur. What is the theoretical yield of iron (II) sulfide?

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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781337399425
BuyFind

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781337399425

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Chapter 9, Problem 69AP
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A favorite demonstration among chemistry instructors, to show that the properties of a compound differ from those of its constituent elements, involves iron filings and powdered sulfur. If the instructor takes samples of iron and sulfur and just mixes them together, the two elements can be separated from one another with a magnet (iron is attracted (o a magnet, sulfur is not). If the instructor then combines and heats the mixture of iron and sulfur, a reaction takes place and the elements combine to form iron (II) sulfide (which is not attracted by a magnet).

:math> Fe ( s ) + S ( s ) FeS ( s )

ppose 5.25 g of iron filings is combined with 12.7 g of sulfur. What is the theoretical yield of iron (II) sulfide?

Expert Solution
Interpretation Introduction

Interpretation:

To determine the theoretical yield of iron (II) sulphide.

Concept Introduction:

A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction.

The limiting reactant in a particular reaction has due to following properties:

  1. Limiting reactant completely reacted in a particular reaction.
  2. Limiting reactant determines the amount of the product in mole.

The theoretical yield of iron (II) sulphide is 8.26 g FeS.

Theoretical yield is also known as calculated yield. Theoretical yield is the amount of product which is theatrically calculates by the amount of limiting agent. It is the maximum amount of product which is formed in any reaction.

Other name of actual yield is observed yield.

The percentage yield is calculated by the actual or observed experimental yield divided by the theoretical yield and multiplied by 100.

The percentage yield can be calculates by the use of following expression:

Actual yield or given yield Theoretical yield or calculated yield ×100%   

Theoretical yield is the greatest amount of a product possible from a reaction, when assume that the reaction goes to 100% competition.

The balance equation for the calcium and oxalate ions is as follows:

Fe(s)+S(s) FeS(s)

Given:

Amount of Fe -=5.25 g

Amount of S = 12.7 g

Calculation:

Number of moles of Fe and S are calculated as follows:

Number of moles=mass in gmolarmass=5.25g55.845  g/mol=0.094 molesFeNumber of moles=mass in gmolarmass=12.7g32.065 g/mol=0.3966 moles S

In the above reaction Fe is a limiting reagent because it reacted completely. Now calculated the theoretical amount of FeS as follows:

0.094 moles Fe×1.00 mole FeS1.00 moles Fe×87.91 g FeS1.00 mole FeS=8.26 g FeS.

The theoretical yield of iron (II) sulphide is 8.26 g FeS.

Explanation of Solution

Theoretical yield is also known as calculated yield. Theoretical yield is the amount of product which is theatrically calculates by the amount of limiting agent. It is the maximum amount of product which is formed in any reaction.

Other name of actual yield is observed yield.

The percentage yield is calculated by the actual or observed experimental yield divided by the theoretical yield and multiplied by 100.

The percentage yield can be calculates by the use of following expression:

Actual yield or given yield Theoretical yield or calculated yield ×100%   

Theoretical yield is the greatest amount of a product possible from a reaction, when assume that the reaction goes to 100% competition.

The balance equation for the calcium and oxalate ions is as follows:

Fe(s)+S(s) FeS(s)

Given:

Amount of Fe -=5.25 g

Amount of S = 12.7 g

Calculation:

Number of moles of Fe and S are calculated as follows:

Number of moles=mass in gmolarmass=5.25g55

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