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Concept explainers
(a)
Interpretation:
The given compound is a
Concept Introduction:
Carbonyl groups are the one which contain a double bond between carbon and oxygen atom.
If a hydroxyl group is attached to a carbonyl group means it is known as carboxyl group. This can be represented as shown below,
The compounds that contain carboxyl functional group are known as carboxylic acids.
(b)
Interpretation:
The given compound is a carboxylic acid or not has to be indicated.
Concept Introduction:
Carbonyl groups are the one which contain a double bond between carbon and oxygen atom. Aldehydes and ketones possess this carbonyl functional group in it. The structural representation of a carbonyl group can be given as shown below,
If a hydroxyl group is attached to a carbonyl group means it is known as carboxyl group. This can be represented as shown below,
The compounds that contain carboxyl functional group are known as carboxylic acids.
(c)
Interpretation:
The given compound is a carboxylic acid or not has to be indicated.
Concept Introduction:
Carbonyl groups are the one which contain a double bond between carbon and oxygen atom. Aldehydes and ketones possess this carbonyl functional group in it. The structural representation of a carbonyl group can be given as shown below,
If a hydroxyl group is attached to a carbonyl group means it is known as carboxyl group. This can be represented as shown below,
The compounds that contain carboxyl functional group are known as carboxylic acids.
(d)
Interpretation:
The given compound is a carboxylic acid or not has to be indicated.
Concept Introduction:
Carbonyl groups are the one which contain a double bond between carbon and oxygen atom. Aldehydes and ketones possess this carbonyl functional group in it. The structural representation of a carbonyl group can be given as shown below,
If a hydroxyl group is attached to a carbonyl group means it is known as carboxyl group. This can be represented as shown below,
The compounds that contain carboxyl functional group are known as carboxylic acids.
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Chapter 16 Solutions
EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
- Which form of aspartic acid in Problem 18.54 is the zwitterion? What is the pI for the zwitterion?arrow_forwardFollowing are Fischer projections for a group of five-carbon sugars, all of which are aldopentoses. Identify the pairs that are enantiomers and the pairs that are epimers. (The sugars shown here are not all of the possible five-carbon )arrow_forwardFollowing are Fischer projection for a group of five carbon sugars,all of which are aldopentoses. Identify the pairs that are enantiomers and the pairs that are epimers.(The sugar shown herebare not all of the possible five carbon sugars.)arrow_forward
- Following are Fischer projections for a group of five-carbon sugars, all of which are aldopentoses. Identify the pairs that are enantiomers and the pairs that are epimers. (The sugars shown here are not all of the possible five-carbon sugars.) 1 СНО 2 СНО СНО Н-С—ОН Н-С—ОН Н—С—ОН Н-С—ОН НО —С—Н Н-С—ОН Н- С—ОН НО—С— Н НО—С—Н CH̟OH CH̟OH ČH̟OH в iоchemistry |61 STATE ATION Republic of the Philippines Romblon State University Romblan, Philippines 4 СНО 5 СНО 6 СНО НО—С—Н Н-С—ОН НО -С—Н Н—С—ОН НО -С—Н НО -С—Н H-C–OH Н-С—ОН НО—С—Н CH,OH ČH,OH CH,OHarrow_forwardGive one specific sample structure (Fischer Projection or Haworth) of the following carbohydrate derivatives: - Amino-sugararrow_forwardDraw the Fischer projection for a monosaccharide.arrow_forward
- Draw the four stereoisomers of threonine as Fischer projections.arrow_forwardHistidine is an amino acid with three titratable groups: an -NH3+ group (pKa = 9.2), a -COOH group (pKa = 1.8), and an imidazole (amine-like) group (pKa = 6.0). The titration curve for histidine is shown below with four points highlighted. (a) Identify which point on the titration curve corresponds to the pKa for each of the titratable groups, and which point corresponds to the pI. Explain your choices. (b) Calculate the value of pI for histidinearrow_forwardFollowing are Fischer projections for a groupof five-carbon sugars, all of which are aldopentoses. Identify thepairs that are enantiomers and the pairs that are epimers. (Thesugars shown here are not all of the possible five-carbon sugars.)arrow_forward
- Which form of lysine in Problem 18.56 is the zwitterion? What is the pI for the zwitterion?arrow_forwardFollowing are Fischer projections for a group of five-carbon sugars, all of which are aldopentoses. Identify the pairs that are enantiomers. CHO сно H-C- OH H-C-OH H-C- OH но-с — н н-с—он но- ČHOH ČH,OH сно CHO Н-с—он но—с— н H-C- OH H-C-OH но—с—н Н-с—он ČHOH ČH,OH сно сно н-с—он но—с —н но—с— н но -с — н H-C- OH но- C-H ČH,OH ČH,OHarrow_forwardFor the first part, draw a Fischer projection formula for the enantiomer of each of the following monosaccharides. For the second part, identify whether the images are in D- or L-configuration. Write your answers first on a piece of bond paper.arrow_forward
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