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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

The action of bacteria on meat and fish produces a compound called cadaverine. As its name and origin imply, it stinks! (It is also present in bad breath and adds to the odor of urine.) It is 58.77% C, 13.81% H, and 27.40% N. Its molar mass is 102.2 g/mol. Determine the molecular formula of cadaverine.

Interpretation Introduction

Interpretation: The empirical and molecular formulas for the given compound should be determined.

Concept introduction:

  • Empirical formula of a compound represents the smallest whole number relative ratio of elements in that compound.
  • Equation for finding Molecular formula from the empirical formula,

    MolarmassEmpiricalformula mass × Empirical formula

  • Equation for number moles from mass and molar mass,

  Numberofmoles=MassingramsMolarmass

  • Mass percent of elements of a compound is the ratio of mass of element to the mass of whole compound and multiplied with hundred.
Explanation

Given

Mass percent of carbon, hydrogen and nitrogen in the given compound cadaverine are 58.77%,13.81%and27.40% respectively.

Mass percent of an element means, 100g of compound contains that mass percent of an element in grams. Therefore, mass of 58.77g carbon 13.81g of hydrogen and 27.40g of nitrogen are present respectively in 100g of cadaverine.

Equation for number moles from mass and molar mass is,

  Numberofmoles=MassingramsMolarmass

Therefore,

The number of moles of carbon is,

    Numberofmoles=58.77g12.01g/mol=4.893mol

The number of moles of hydrogen is,

    Numberofmoles=13.81g1g/mol=13.81mol

The number of moles of nitrogen is,

    Numberofmoles=27.40g14g/mol=1.957mol

So, the mole ratio between elements in cadaverine is,

    C:H:N =4

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