Chapter 2.8, Problem 3.3ACP

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# Atmospheric argon is a mixture of three stable isotopes. 36Ar. 38Ar, and 40Ar. Use the information in the table below to determine the atomic mass and natural abundance of 40Ar.

Interpretation Introduction

Interpretation: The atomic mass and natural abundance for given 40Ar has to be determined from the given data’s of other isotopes.

Concept Introduction:

The average mass of argon is 39.948 u.

Equation for average weight is,

average mass=(%abundanceisotop-1100)×(massofisotop-1) +(%abundanceisotop-2100)×(massofisotop-2)+etc

Two species are said to be isotopes if they have same atomic number but different mass number.

Explanation

There are three isotopes for argon atom.

The mass of isotope-1 is 35.967545u and its abundance is 0.337%.

The mass of isotope-2 is 37.96732u and its abundance is 0.063%.

Therefore, abundance of isotope-3 is 100%-(0.337%+0.063%)=99.6%

Equation for average weight is,

Â Â Â Â averageÂ weightâ€‰â€‰=â€‰â€‰(%abundanceâ€‰isotop-1100)â€‰â€‰Ã—â€‰(massâ€‰ofâ€‰isotop-1)â€‰ +â€‰(%abundanceâ€‰isotop-2100)â€‰â€‰Ã—â€‰(massâ€‰ofâ€‰isotop-2)â€‰+â€‰etc

Therefore,

averageÂ weightâ€‰ofâ€‰argonâ€‰=â€‰â€‰(0.337100)â€‰â€‰Ã—â€‰(35

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