Chapter 2.8, Problem 3.2ACP

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

The density of a mixture of gases may be calculated by summing the products of the density of each gas and the fractional volume of space occupied by that gas. (Note the similarity to the calculation of the molar mass of an element from the isotopic masses and fractional abundances.) Assume dry air with CO2 removed is 20.96% (by volume) oxygen. 78.11% nitrogen, and 0.930% argon. Determine the density of argon.

Interpretation Introduction

Interpretation: The density of argon in given air sample has to be calculated using the given volume fraction of Argon 0.930%.

Concept introduction:

Equation for density from volume and mass is,

Density=MassVolume

The density of air determined by summing the products of volume fraction and density of given gases.

Explanation

The density of dry air is 1.29327g/L.

The volume fraction of CO2 gas is 20.96%=0.2096L

The density of CO2 is 1.42952g/L.

The volume fraction of nitrogen gas is 78.11%=0.7811L .

The density of the nitrogen is 1.25092g/L.

The volume fraction of argon is 0.930%=0.0093L

Equation for density from volume and mass is,

Â Â Â Â Densityâ€‰â€‰=

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