# Tocalculate : f ( 0 ) , f ( 2 ) , f ( − 2 ) , f ( a ) , f ( − a ) , f ( x + 1 ) , f ( 2 x ) and 2 f ( x ) − 2.

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 2, Problem 9RE
To determine

## Tocalculate: f(0), f(2), f(−2), f(a), f(−a), f(x+1), f(2x) and 2f(x)−2.

Expert Solution

The answer is f (0) = 6, f (2) = 2, f (2) = 18,

f (a) = a24a + 6,

f (a) = a2+4a+6,

f(x+1)=x22x+3,

f(2x)=4x28x+6,

2f(x)2=2x28x+10.

### Explanation of Solution

Given information : The equation of f(x) is given = f(x)=x24x+6 .

Formula used : To find f (a) put x=a in the equation of f(x).

Calculation :

The equation of f (x) = x24x+6 .

f(0)= (0) 2 4(0)+6f(0)=00+6f(0)=6

f(2)= (2) 2 4(2)+6f(2)=48+6f(2)=2

f(2)= (2) 2 4(2)+6f(2)=4+8+6f(2)=18

f(a)= (a) 2 4(a)+6f(a)=a24a+6

f(a)= (a) 2 4(a)+6f(a)=a2+4a+6

f(x+1)= (x+1) 2 4(x+1)+6f(x+1)=x2+2x+14x4+6f(x+1)=x22x+3

f(2x)= (2x) 2 4(2x)+6f(2x)=4x28x+6

2f(x)2=2( x 2 4x+6)22f(x)2=2x28x+1222f(x)2=2x28x+10

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