BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 2.7, Problem 16E
To determine

To prove the function h(x)=x3+8 is one-to-one function

Expert Solution

Answer to Problem 16E

  x1=x2

Yes it isaone-to-one function

Explanation of Solution

Given information:

  h(x)=x3+8

Calculation:

Put x=x1,x2

Therefore,

  h(x1)=x13+8

And

  h(x2)=x23+8

For one-to-one

  h(x1)=h(x2)

  x13+8=x23+8 [Subtract 8 from both the sides]

  x13=x23 [Remove cube root from both the sides]

Hence x1=x2

So it is a one-to-one function

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