BuyFind

Single Variable Calculus: Concepts...

4th Edition
James Stewart
Publisher: Cengage Learning
ISBN: 9781337687805
BuyFind

Single Variable Calculus: Concepts...

4th Edition
James Stewart
Publisher: Cengage Learning
ISBN: 9781337687805

Solutions

Chapter 2.2, Problem 6E

a.

To determine

To find the value of each quantity if it does not exist explain why.

Expert Solution

Answer to Problem 6E

  4

Explanation of Solution

Given:

  limx3h(x)

Calculation:

The given graph is

  Single Variable Calculus: Concepts and Contexts, Enhanced Edition, Chapter 2.2, Problem 6E , additional homework tip  1

  limx3h(x)

As x approaches -3 from the left, h(x) approaches 4

b.

To determine

To find the value of each quantity if it does not exist explain why.

Expert Solution

Answer to Problem 6E

  4

Explanation of Solution

Given:

  limx3+h(x)

Calculation:

The given graph is

  Single Variable Calculus: Concepts and Contexts, Enhanced Edition, Chapter 2.2, Problem 6E , additional homework tip  2

  limx3+h(x)

As x approaches -3 from the left, h(x) approaches 4

c.

To determine

To find the value of each quantity if it does not exist explain why.

Expert Solution

Answer to Problem 6E

  4

Explanation of Solution

Given:

  limx3h(x)

Calculation:

The given graph is

  Single Variable Calculus: Concepts and Contexts, Enhanced Edition, Chapter 2.2, Problem 6E , additional homework tip  3

  limx3h(x)

As x approaches -3 from the left, h(x) approaches 4

d.

To determine

To find the value of each quantity if it does not exist explain why.

Expert Solution

Answer to Problem 6E

  4

Explanation of Solution

Given:

  h(3)

Calculation:

The given graph is

  Single Variable Calculus: Concepts and Contexts, Enhanced Edition, Chapter 2.2, Problem 6E , additional homework tip  4

  h(3)

As x approaches -3 from the left, h(x) approaches 4

e.

To determine

To find the value of each quantity if it does not exist explain why.

Expert Solution

Answer to Problem 6E

  1

Explanation of Solution

Given:

  limx0h(x)

Calculation:

The given graph is

  Single Variable Calculus: Concepts and Contexts, Enhanced Edition, Chapter 2.2, Problem 6E , additional homework tip  5

  limx0h(x)

Looking at the graph, we can see that the function approaches (and actually reaches) 1 as x approaches 0 from the left side.

f.

To determine

To find the value of each quantity if it does not exist explain why.

Expert Solution

Answer to Problem 6E

  1

Explanation of Solution

Given:

  limx0+h(x)

Calculation:

The given graph is

  Single Variable Calculus: Concepts and Contexts, Enhanced Edition, Chapter 2.2, Problem 6E , additional homework tip  6

  limx0+h(x)

Looking at the graph, we can see that the function approaches (and actually reaches) 1 as x approaches 0 from the right side.

g.

To determine

To find the value of each quantity if it does not exist explain why.

Expert Solution

Answer to Problem 6E

Doesn’t exist.

Explanation of Solution

Given:

  limx0h(x)

Calculation:

The given graph is

  Single Variable Calculus: Concepts and Contexts, Enhanced Edition, Chapter 2.2, Problem 6E , additional homework tip  7

  limx0h(x)

Since the left hand limit and the right hand limit are not equal, the limit doesn’t exist.

h.

To determine

To find the value of each quantity if it does not exist explain why.

Expert Solution

Answer to Problem 6E

  1

Explanation of Solution

Given:

  h(0)

Calculation:

The given graph is

  Single Variable Calculus: Concepts and Contexts, Enhanced Edition, Chapter 2.2, Problem 6E , additional homework tip  8

  h(0)

  h(0)=1

i.

To determine

To find the value of each quantity if it does not exist explain why.

Expert Solution

Answer to Problem 6E

  2

Explanation of Solution

Given:

  limx2h(x)

Calculation:

The given graph is

  Single Variable Calculus: Concepts and Contexts, Enhanced Edition, Chapter 2.2, Problem 6E , additional homework tip  9

  limx2h(x)

As x approaches 2 from the left, h(x) approaches 2

j.

To determine

To find the value of each quantity if it does not exist explain why.

Expert Solution

Answer to Problem 6E

  2

Explanation of Solution

Given:

  h(2)

Calculation:

The given graph is

  Single Variable Calculus: Concepts and Contexts, Enhanced Edition, Chapter 2.2, Problem 6E , additional homework tip  10

  h(2)=2

As x approaches 2 , h(x) approaches 2

k.

To determine

To find the value of each quantity if it does not exist explain why.

Expert Solution

Answer to Problem 6E

  3

Explanation of Solution

Given:

  limx5+h(x)

Calculation:

The given graph is

  Single Variable Calculus: Concepts and Contexts, Enhanced Edition, Chapter 2.2, Problem 6E , additional homework tip  11

  limx5+h(x)

As x approaches 5 from the right, h(x) approaches 3

l.

To determine

To find the value of each quantity if it does not exist explain why.

Expert Solution

Answer to Problem 6E

Does not exist.

Explanation of Solution

Given:

  limx5h(x)

Calculation:

The given graph is

  Single Variable Calculus: Concepts and Contexts, Enhanced Edition, Chapter 2.2, Problem 6E , additional homework tip  12

  limx5h(x)

The behavior of the graph is not clear when x approaches 5 from left.

Hence limit doesn’t exist.

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