Concept explainers
(a)
Interpretation:
To explain if the use of the container at given temperature is safe using the given values in the question and based on Raoult’s Law.
Concept introduction:
Raoult’s Law can be used to find the molecular mass of an unknown solute like in this question we need to find the partial pressure of water.
Antoine equation is an empirical equation
Where A, B, C are the coefficients and T is the temperature.
Mole fraction can be defined as the ratio of one of the components to the total mixture of the substances given by:
(b)
Interpretation:
To explain the assumption regarding no change in liquid composition is reasonable.
Concept introduction:
Raoult’s can be used to find the molecular mass of an unknown solute like in this question we need to find the partial pressure of water.
Let us assume, the vapor to be an ideal gas. So, the pressure is directly proportional to the temperature given by:
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EBK ELEMENTARY PRINCIPLES OF CHEMICAL P
- A mixture of isobutylene ((CH3)2CCH2, 0.400 bar partial pressure) and HCI (0.600 bar partial pressure) is heated at 500.0 K. The equilibrium constant K for the gas- phase thermal decomposition of tert- butyl chloride ((CH3)3CCI) is 3.45 at 500.0 K. bar (CH3);CCI(g) = (CH3)2CCH2(g) + HCI(g) 1 3 What is the partial pressure of isobutylene ((CH3)2CCH2) at equilibrium? 4 C 8. 9. +/- х 100arrow_forwardA mixture of isobutylene ((CH3)2CCH2, 0.400 bar partial pressure) and HCI (0.600 bar partial pressure) is heated at 500.0 K. The equilibrium constant K for the gas- phase thermal decomposition of tert- butyl chloride ((CH3)3CCI) is 3.45 at 500.0 K. bar (CH3);CCI(g) = (CH3)2CCH2(g) + HCI(g) 1 3 What is the partial pressure of hydrochloric acid (HCI) at equilibrium? 4 C 8. 9. +/- х 100arrow_forwardA mixture of isobutylene ((CH3)2CCH2, 0.400 bar partial pressure) and HCI (0.600 bar partial pressure) is heated at 500.0 K. The equilibrium constant K for the gas- phase thermal decomposition of tert- butyl chloride ((CH3)3CCI) is 3.45 at 500.0 K. bar (CH3);CCI(g) = (CH3)2CCH2(g) + HCI(g) 1 3 You have calculated the equilibrium partial pressures to be: 4 C tert-butyl chloride,CH3);CCI = (x) hydrochloric acid, HCI = (0.600 - x) isobutylene, (CH3)2CCH2 = (0.400 - x) What is the partial pressure of tert- butyl chloride ((CH3)3CCI) at equilibrium? 8. 9. +/- х 100arrow_forward
- A parcel of unsaturated air contains a mixture of dry air and water vapor. The specific humidity q of the air parcel is 12 g kg^−1. Recall that q = Mv / (Mv+Md),where Mv is the mass of the water vapor and Md is the mass of the dry air. This is equivalent to what we have been calling the fractional concentration of water vapor by mass. (a) If the air parcel is at a temperature T= 25◦C , what is the virtual temperature of the air parcel? (b) If the air parcel is at a temperature T= 25◦C and a pressure of 1000 hPa, what is the relative humidity of the air parcel? (c) What is the apparent molar mass of the air parcel?arrow_forwardUse only the first decimal points (X.X) for atomic masses. R = 8.314 L*kPa/mole*K. In a reactor at 350.0 kPA and 95 °C, HCl adds to acetylene by the following reaction:2HCl(g) + C2H2(g) --> C2Cl2H4(g)39.1 g of HCl and 39.1 g of acetylene are placed into the reactor. What is the limiting reagent? What is the final volume of the system?arrow_forward7. The solubility, C, of sucrose in water, expressed as grams of sucrose per 100 g of solvent, is given as below t/°C C/g 0 179.2 10 20 203.9 190.5 30 219.5 [ΔΗ (a) Draw an appropriate graph to determine the molar enthalpy of solution of sucrose in the temperature range 0 to 40°C. (b) 50mL of saturated solution of benzoic acid at 25°C requires 12.8 mL of 0.05 M NaOH to completely neutralize. What is the solubility of benzoic acid in g/L water at 25°C. so ln,m 40 238.1 = 4.96 kJ/mol, Cbenzoic acid = 1.56g/L]arrow_forward
- Water and acetonitrile, CH3CN, are miscible (can be mixed in any proportions). However, whenwater and acetonitrile are mixed, the volumes are not additive (the total volume of the resultingsolution is not equal to the sum of the pure liquid volumes). For example, when 100.0 mL ofwater and 100.0 mL of CH3CN(l), are mixed at 20 °C, the total volume of the solution is 192.0mL,not 200.0 mL.a. Provide an explanation for this phenomenon.b. Calculate the molarity, molality and mol fraction of CH3CN in a solution preparedby mixing 100.0 mL of water and 100.0 mL of CH3CN(l) at 20 °C. The total volume of themixture is 192.0 mL and the densities of water and acetonitrile are 0.998 g/mL and 0.782g/mL, respectively, at this temperature.c. When 70.0 g H2O and 190.0 g CH3CN(l) are mixed, to resulting solution has adensity of 0.860 g/mL at 20 °C. Calculate the volumes of the pure liquid samples and thesolution, and show that the pure liquid volumes are not additive.arrow_forwardA mixture combining 60 mL ethanol (C₂H6O) with 75 mL water (H₂O) is prepared at 280 K. The partial molar volumes of ethanol (E) and water (W) when mixed in these proportions (right column below) and in pure form (left column below) are ethanol water pure substance molar volume 58.2 mL/mol 18.00 mL/mol partial molar volume 55.3 mL/mol 17.7 mL/mol Determine the volume of the ethanol-water mixture. [Hint: You will need to determine the moles of each component.]arrow_forwardA quantity of methyl acetate is placed in an open, transparent, three-liter flask and boiled long enough to purge all air from the vapor space. The flask is then sealed and allowed to equilibrate at 30°C, at which temperature methyl acetate has a vapor pressure of 269 mm Hg. Visual inspection shows 10 mL of liquid methyl acetate present.(a) What is the pressure in the flask at equilibrium? Explain your reasoning.(b) What is the total mass (grams) of methyl acetate in the flask? What fraction is in the vapor phase atequilibrium?(c) The above answers would be different if the species in the vessel were ethyl acetate because methyl acetate and ethyl acetate have different vapor pressures. Give a rationale for that difference.arrow_forward
- A geochemist in the field takes a 9.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X. He notes the temperature of the pool, 15. C, and caps the sample carefully. Back in the lab, the geochemist first dilutes the sample with distilled water to 400. mL.. Then he filters and evaporates all the water under vacuum. Crystals of X are left behind. The researcher washes, dries and weighs the crystals. They weigh 0.045 g. Using only the information above, can you calculate the solubility of Xin water at 15.° C7 If you said yes, calculate it. Be sure your answer has a unit symbol and 2 significant digits. yes O no 0 0.9 H ロ・ロ X 0 Garrow_forwardA mixture of isobutylene ((CH3)2CCH2, 0.400 bar partial pressure) and HCI (0.600 bar partial pressure) is heated at 500.0 K. The equilibrium constant K for the gas-phase thermal decomposition of tert-butyl chloride ((CH3)3CCI) is 3.45 at 500.0 K. (CH3);CCI(g) = (CH3),CCH2(g) + HCI(g) Based on your ICE table, set up the expression for K for the decomposition of (CH3);CCI. (CH3);CCI(g) = (CH3)2CCH2(g) + HCI(g) 1 Do not combine or simplify terms. K = 3.45 5 RESET (P(CH);CCH;) (P(CH,);CCH,)? (PHCI) (Рнс) (P(CH,),cCi) (P(CH,),CCI)? 2(Рнс) 2(P(CH3),CCH;) 2(P(CH,),CCI) 2(P(CH,),CCI)? 2(Рнс)? 2(P(CH3),C=CH,)?arrow_forwardA student investigates the enthalpy of solution, ΔHsoln, for two alkali metal halides, KCl and RbCl. Inaddition to the salts, the students has access to a calorimeter, a balance with a precision of ±0.1 g,and a thermometer with a precision of ±0.1°C.a. To measure ΔHsoln for KCl, the student adds 100.0 g of water initially at 25.0°C to acalorimeter and adds 20.0 g of KCl(s), stirring to dissolve. After the KCl dissolvescompletely, the maximum temperature reached by the solution is 55.4°C. Question : Determine the value of ΔHsoln for KCl in kJ/molrxnarrow_forward
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