BuyFind

Single Variable Calculus: Concepts...

4th Edition
James Stewart
Publisher: Cengage Learning
ISBN: 9781337687805
BuyFind

Single Variable Calculus: Concepts...

4th Edition
James Stewart
Publisher: Cengage Learning
ISBN: 9781337687805

Solutions

Chapter 1.6, Problem 37E

(a)

To determine

To find: The exact value of the expression.

Expert Solution

Answer to Problem 37E

The exact value of the expression is 3 .

Explanation of Solution

Given information:

The given expression is,

  log26log215+log220

Concept used:

Consider the property of the logarithmic function,

  logaax=x

The given expression is calculated as,

  log26log215+log220=log2(615)+log220=log2(615×20)=log223=3

Therefore, the exact value of the expression is 3 .

(b)

To determine

To find: The exact value of the expression.

Expert Solution

Answer to Problem 37E

The exact value of the expression is 2 .

Explanation of Solution

Given information:

The given expression is,

  log3100log318log350

Concept used:

Consider the property of the logarithmic function,

  logaax=x

The given expression is calculated as,

  log3100log318log350=log3(10018)log350=log3(10018×50)=log332=2

Therefore, the exact value of the expression is 2 .

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