Propane is burned completely with excess oxygen. The product gas contains 24.5 mole% CO2, 6.10% CO. 40.8% H2O. and 28.6% O2.
- Calculate the percentage excess O2 fed to the furnace.
3CO2 + 3CO + 8H2O
According to this equation. CO2 and CO should be in a ratio of 1/1 in the reaction products, but in the product gas of Part (a) they are in a ratio of 24.8/6.12. Is that result possible? (Hint: Yes.) Explain how.
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