# To simplify 6 3 + 2 by using appropriate operations. ### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071 ### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1, Problem 63RE
To determine

## To simplify 63+2 by using appropriate operations.

Expert Solution

### Explanation of Solution

Given information:

63+2

Formula used:

Rationalizing the denominator − A+BC

multiplying numerator and denominator by conjugate radical ABC

Square root rule( Distributing) :- A×B=AB

Distributing Property:- a(b+c)=ab+ac

Difference of Squares :- A2B2=(AB)(A+B)

Calculations:

=63+2

Multiplying denominator and numerator by 32 .

=63+2×3232=6(3+2)(3+2)(32)=6(3+2)32=6(3+2)1=6(3+2)=6(3)+6(2)

=32+23 ( because 6=2×3=23 )

After simplifying we get 32+23 .

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