BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.1, Problem 30E

(a)

To determine

To find: the simplest value of 2341213 .

Expert Solution

Answer to Problem 30E

  2341213=152

Explanation of Solution

Given information:

An expression is given as 2341213 .

Formula used:

Difference of two fraction ab and cd can be performed by

  abcd=abcbbd

Product of two fraction ab and cd can be performed by

  abcd=acbd

Quotient of two fraction ab and cd can be performed by

  abcd=adbc

Calculation:

Consider the given expression.

  2341213

Now, simplify the expression as shown:

  2341213=24343232=5416=5461=152

Here, the simplified value is 152 .

(b)

To determine

To find: the simplest value of 25+12110+315 .

Expert Solution

Answer to Problem 30E

  25+12110+315=3

Explanation of Solution

Given information:

An expression is given as 25+12110+315 .

Formula used:

Sum of two fraction ab and cd can be performed by

  ab+cd=ab+cbbd

Product of two fraction ab and cd can be performed by

  abcd=acbd

Quotient of two fraction ab and cd can be performed by

  abcd=adbc

Calculation:

Consider the given expression.

Now, simplify the expression as shown:

  25+12110+315=22+515215+3101015=91045150=91015045=3

Here, the simplified value is 3 .

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