BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.5, Problem 101E
To determine

All the real solution of equation.

Expert Solution

Answer to Problem 101E

The equation has three distinct real solutions.

  x=0x=1x=3

Explanation of Solution

Given information:

  4(x+1)125(x+1)32+(x+1)52=0

  4(x+1)125(x+1)32+(x+1)52=0

Taking (x+1)12 as a common factor from above equation

  (x+1)12[45(x+1)+(x+1)2]=0=(x+1)12[45x+5+x2+2x+1]=0=(x+1)12[x23x]=0

Taking x common from x23x :

  x(x+1)12(x3)=0

Therefor,

  x=0

  x3=0x=3

  (x+1)12=0x+1=0x=1

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