BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.8, Problem 49E
To determine

To calculate: Whether the set of points (0,0),(1,0) and (1,1) lie on the graph of the equation x2y1=0

Expert Solution

Answer to Problem 49E

The points (1,0) and (1,1)lie on the graph of the equation whereas the point (0,0)does not lie on the graph.

Explanation of Solution

Given information:

The set of points (0,0),(1,0) and (1,1) and equation of graph x2y1=0 .

Formula used:

The set of all points (x,y) in the Cartesian plane or coordinate plane that satisfy the equation is known as the graph of the equation in x and y coordinates.

Calculation:

Consider the providedset of points (0,0),(1,0) and (1,1) and equation of graph x2y1=0 .

Recall that the set of all points (x,y) in the Cartesian plane or coordinate plane that satisfy the equation is known as the graph of the equation in x and y coordinates.

Substitute the point (0,0) in the equation x2y1=0 and check whether left hand side is equal to right hand side.

  (0)2(0)1=01=0

The above equality does not hold so, the point (0,0) does not lie on the graph of the equation.

Substitute the point (1,0) in the equation x2y1=0 and check whether left hand side is equal to right hand side.

  (1)2(0)1=011=00=0

The above equality holds true so, the point (1,0) lie on the graph of the equation.

Substitute the point (1,1) in the equation x2y1=0 and check whether left hand side is equal to right hand side.

  (1)2(1)1=01+21=02+2=00=0

The above equality holds true so, the point (1,1) lie on the graph of the equation.

Thus, the points (1,0) and (1,1) lie on the graph of the equation whereas the point (0,0) does not lie on the graph.

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