# the simplest value of 2 2 3 − 2 3 2 . ### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071 ### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1.1, Problem 29E

(a)

To determine

## To find: the simplest value of 223−232 .

Expert Solution

223232=83

### Explanation of Solution

Given information:

An expression is given as 223232 .

Formula used:

Difference of two fraction ab and cd can be performed by

abcd=abcbbd

Product of two fraction ab and cd can be performed by

abcd=acbd

Quotient of two fraction ab and cd can be performed by

Calculation:

Consider the given expression.

223232

Now, simplify the expression as shown:

223232=222323223=44943=494934=364934=32934=83

Here, the simplified value is 83 .

(b)

To determine

Expert Solution

1121819=6

### Explanation of Solution

Given information:

An expression is given as 1121819 .

Formula used:

Difference of two fraction ab and cd can be performed by

abcd=abcbbd

Product of two fraction ab and cd can be performed by

abcd=acbd

Quotient of two fraction ab and cd can be performed by

Calculation:

Consider the given expression.

Now, simplify the expression as shown:

1121819=1129889=112172=112721=6

Here, the simplified value is 6 .

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