# Tofind: the value of k at which x has a real solution.

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1.5, Problem 120E
To determine

## Tofind:the value of k at which x has a real solution.

Expert Solution

For x=2 the value of k is not-defined remaining all integer of x the value of k is obtained the solution of the given function will be x:x2.

### Explanation of Solution

Given:

3x+k-5=kx-k+1 .

Concept used:

If denominator of the fraction is 0 then the fraction is not defined so the solution doesn’t exists.

Mathematically:

xy where y0.

Calculation:

3x+k-5=kx-k+1 .

2k-kx=6-3x .

k(2-x)=6-3x .

k=6-3x2-x .

x=0; k=3 .

x=1; k=3 .

x=2; not possible .

Hence, For x=2 the value of k is not-defined remain all integer of x the value of k is obtained hence, the solution of the given function will be x:x2.

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