BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.3, Problem 127E
To determine

To calculate: The common factor of the expression (x2+3)1/323x2(x2+3)4/3 .

Expert Solution

Answer to Problem 127E

The common factor of the expression (x2+3)1/323x2(x2+3)4/3 is (x2+3)4/3(13x2+3) .

Explanation of Solution

Given information:

The expression (x2+3)1/323x2(x2+3)4/3 .

Formula used:

To factor out the common factor from a polynomial, find out the greatest common factor and express the polynomial as a product of the simpler ones.

Calculation:

Consider the given expression (x2+3)1/323x2(x2+3)4/3 .

Recall that to factor out the common factor from a polynomial, find out the greatest common factor and express the polynomial as a product of the simpler ones.

Here, the terms have the common factor (x2+3)4/3 .

So, (x2+3)1/323x2(x2+3)4/3 can be written in simplified form as,

  (x2+3)1/323x2(x2+3)4/3=(x2+3)4/3[(x2+3)1/3(x2+3)4/323x2]=(x2+3)4/3(x2+323x2)=(x2+3)4/3(323x2+3)=(x2+3)4/3(13x2+3)

Thus, the common factor of the expression (x2+3)1/323x2(x2+3)4/3 is (x2+3)4/3(13x2+3) .

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