# the distance between earth and sunin scientific notation.

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1.2, Problem 82E

a)

To determine

## To write: the distance between earth and sunin scientific notation.

Expert Solution

93millionmiles=9.3×107

### Explanation of Solution

Given information:

The distance between earth and sunis 93millionmiles .

Concept used:

Scientific notation:

A notation in which a given quantity can be expressed as a number with significant digits required for a specified degree of accuracy and multiplied by 10 to the appropriate power.

Calculation:

Consider the given number.

93millionmiles

So, the number can be expressed in scientific notation as

93millionmiles=93000000=9.3×10000000=9.3×107

Hence, 93millionmiles=9.3×107

b)

To determine

### To write: the mass of an oxygen molecule in scientific notation.

Expert Solution

0.000000000000000000053=53×1020 g

### Explanation of Solution

Given information:

The mass of oxygen molecule is 0.000000000000000000053 g.

Concept used:

Scientific notation:

A notation in which a given quantity can be expressed as a number with significant digits required for a specified degree of accuracy and multiplied by 10 to the appropriate power.

Calculation:

Consider the given number.

0.000000000000000000053

So, the number can be expressed in scientific notation as

0.000000000000000000053=5.3÷10000000000000000000=5.3÷1020=5.3×1020

Hence, 0.000000000000000000053=53×1020 g

c)

To determine

### To write: the mass of earth in scientific notation.

Expert Solution

5,970,000,000,000,000,000,000,000=5.97×1021 kg

### Explanation of Solution

Given information:

5,970,000,000,000,000,000,000,000

Concept used:

Scientific notation:

A notation in which a given quantity can be expressed as a number with significant digits required for a specified degree of accuracy and multiplied by 10 to the appropriate power.

Calculation:

Consider the given number.

5,970,000,000,000,000,000,000,000 kg

So, the number can be expressed in scientific notation as

5,970,000,000,000,000,000,000,000=5.97×100000000000000000000=5.97×1021

Hence, 5,970,000,000,000,000,000,000,000=5.97×1021 kg.

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