# the statement “ y is negative” in terms of inequality. ### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071 ### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1.1, Problem 38E

(a)

To determine

## To write: the statement “ y is negative” in terms of inequality.

Expert Solution

y<0

### Explanation of Solution

Given information:

y is negative

Calculation:

Consider the given statement.

y is negative

Now, negative number is always less than 0.

So, y<0 .

(b)

To determine

Expert Solution

z>1

### Explanation of Solution

Given information:

z is greater than 1.

Calculation:

Consider the given statement.

z is greater than 1

Now, greater than sign is '>' .

So, z is greater than 1, in terms of an inequality can be written as

z>1 .

(c)

To determine

Expert Solution

b8

### Explanation of Solution

Given information:

b is at most 8 .

Calculation:

Consider the given statement.

b is at most 8

Now, for the word “at most” the required symbol is '' .

So, b is at most 8 , in terms of an inequality can be written as

b8 .

(d)

To determine

Expert Solution

0<w17

### Explanation of Solution

Given information:

w is positive and less than equal to 17

Calculation:

Consider the given statement.

w is positive and less than equal to 17

Now, greater than sign is '>' and less than equal to symbol is '' .

So, w is positive and less than equal to 17 , in terms of an inequality can be written as

0<w17 .

(e)

To determine

Expert Solution

|yπ|2

### Explanation of Solution

Given information:

The distance between y and π is at least 2 .

Calculation:

Consider the given statement.

The distance between y and π is at least 2 .

Distance between two points a and b can be written as

d(a,b)=|ab|

Now, for the word “at least” the required symbol is '' .

So, the distance between y and π is at least 2 , in terms of an inequality can be written as

d(y,π)2|yπ|2 .

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