BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.6, Problem 42E
To determine

To find: The length and width of the parcel.

Expert Solution

Answer to Problem 42E

The length of parcel is 246 ft and the width of parcel is 240 ft.

Explanation of Solution

Given:

The length of parcel is 6 ft more than its width.

The length of each diagonal is 174 ft.

Calculation:

Let the width of parcel be x.

Tabulate the given information into the language of algebra.

In words In Algebra
Width of parcel x
Length of parcel x+6

Model the equation for the above information.

(Length)2+(Width)2=(Diagonal)2x2+(x+6)2=(174)2

Simplify the above equation for x,

x2+x2+36+12x=302762x2+12x30240=0(x+126)(x240)=0x=240,x=126

The width of rectangle cannot be negative. So the width of parcel is 240 ft.

The length of parcel is,

Length=x+6=240+6=246

The length of parcel is 246 ft.

Thus, the length of parcel is 246 ft and the width of parcel is 240 ft.

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