# The length and width of the parcel. ### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071 ### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1.6, Problem 42E
To determine

## To find: The length and width of the parcel.

Expert Solution

The length of parcel is 246 ft and the width of parcel is 240 ft.

### Explanation of Solution

Given:

The length of parcel is 6 ft more than its width.

The length of each diagonal is 174 ft.

Calculation:

Let the width of parcel be x.

Tabulate the given information into the language of algebra.

 In words In Algebra Width of parcel x Length of parcel x+6

Model the equation for the above information.

(Length)2+(Width)2=(Diagonal)2x2+(x+6)2=(174)2

Simplify the above equation for x,

x2+x2+36+12x=302762x2+12x30240=0(x+126)(x240)=0x=240,x=126

The width of rectangle cannot be negative. So the width of parcel is 240 ft.

The length of parcel is,

Length=x+6=240+6=246

The length of parcel is 246 ft.

Thus, the length of parcel is 246 ft and the width of parcel is 240 ft.

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