# The expression 1 x + 1 − 2 ( x + 1 ) 2 + 3 x 2 − 1 ### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071 ### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1.4, Problem 58E
To determine

## To calculate: The expression 1x+1−2(x+1)2+3x2−1

Expert Solution

1x+12(x+1)2+3x21=x2+x+4(x1)(x+1)2

### Explanation of Solution

Given information:

Given expression is 1x+12(x+1)2+3x21

Consider the expression as 1x+12(x+1)2+3x21

This expression can re- written as,

1x+12(x+1)2+3x21=1x+12(x+1)2+3(x1)(x+1)

Take L.C.M.,

1x+12(x+1)2+3(x1)(x+1)=(x+1)(x1)2(x1)+3(x+1)(x1)(x+1)2=x212x+2+3x+3(x1)(x+1)2=x2+x+4(x1)(x+1)2

Therefore, 1x+12(x+1)2+3x21=x2+x+4(x1)(x+1)2

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