BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.5, Problem 99E
To determine

Find the real solutions of equation.

Expert Solution

Answer to Problem 99E

  x=±33,x=±22

Explanation of Solution

Given information:

  x435x23+6=0

Formula used: -

  x=b±b24ac2a

  x435x23+6=0

Assuming x23=z in above equation, new equation will be:

  z25z+6=0

Now using x=b±b24ac2a in the equation z25z+6=0

  a=1,b=5,c=6

  a=1,b=5,c=6z=(5)±(5)24(1)(6)2(1)z=5±25242z=5±12z=5±12

  z=5+12,z=512z=3,z=2

Now substituting value of z=x23 in place of z

  x23=3,x23=2x=332,x=232x=±33,x=±22

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