BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.1, Problem 28E

(a)

To determine

To find: the simplest value of (3+14)(145) .

Expert Solution

Answer to Problem 28E

  (3+14)(145)=118

Explanation of Solution

Given information:

An expression is given as (3+14)(145) .

Formula used:

Difference of two fraction ab and cd can be performed by

  abcd=abcbbd

Product of two fraction ab and cd can be performed by

  abcd=acbd

Calculation:

Consider the given expression.

  (3+14)(145)

Now, simplify the expression as shown:

  (3+14)(145)=34141542=1214542=11412=118

Here, the simplified value is 118 .

(b)

To determine

To find: the simplest value of (12+13)(1213) .

Expert Solution

Answer to Problem 28E

  (12+13)(1213)=536

Explanation of Solution

Given information:

An expression is given as (12+13)(1213) .

Formula used:

Sum of two fraction ab and cd can be performed by

  ab+cd=ab+cbbd

Difference of two fraction ab and cd can be performed by

  abcd=abcbbd

Product of two fraction ab and cd can be performed by

  abcd=acbd

Calculation:

Consider the given expression.

Now, simplify the expression as shown:

  (12+13)(1213)=13+1223131223=3+26326=5616=536

Here, the simplified value is 536 .

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