BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.7, Problem 60E
To determine

To solve: the nonlinear inequality. Express the solution using interval notation and graph the solution set.

Expert Solution

Answer to Problem 60E

  x(,53)(32,) .

Explanation of Solution

Given:

The given inequality is 2<x+1x3 .

Concept used:

Guidelines for solving nonlinear inequality:

  1. Move all terms to one side.
  2. Factor the non-zero side of the inequality.
  3. Find the value for which each factor is zero. The number will divide the real lines into interval. List the interval determined by these numbers
  4. Make a table or diagram by using test values of the signs of each factor on each interval. In the last row of the table determining the sign of the product of these factors.
  5. Determine the solution of the inequality from the last row of the sign table.

Calculation:

The given inequality can be expressed as

  x+1x3+2>0{add both sides from 2}x+1+2(x3)x3>0{simplify}3x5x3>0{simplify} .

Firstto find the zeros of the expression in the numerator and demniminator, then

  3x5=0x=53x3=0x=0

From the two zeros above, it extracts the following intervals:

  (,53)(53,3)(3,)

Now, make a table by using test values of the signs of each factor on each interval.

    (,53)(53,3)(3,)
    (2x+6)++
    (x2)+
    quotient++

As it is seen that quotient is less thanin the interval (3,2) .

Hence,the solution set is x(,53)(32,) .

The graph of the non-linear inequality 4x2x+3>2 is:

  Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.7, Problem 60E

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