BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.8, Problem 52E
To determine

To calculate: Whether the set of points (0,1),(12,12) and (32,12) lie on the graph of the equation x2+y2=1 .

Expert Solution

Answer to Problem 52E

The points (0,1),(12,12) and (32,12) lie on the graph of the equation.

Explanation of Solution

Given information:

The set of points (0,1),(12,12) and (32,12) and equation of graph x2+y2=1 .

Formula used:

The set of all points (x,y) in the Cartesian plane or coordinate plane that satisfy the equation is known as the graph of the equation in x and y coordinates.

Calculation:

Consider the providedset of points (0,1),(12,12) and (32,12) and equation of graph x2+y2=1 .

Recall that the set of all points (x,y) in the Cartesian plane or coordinate plane that satisfy the equation is known as the graph of the equation in x and y coordinates.

Substitute the point (0,1) in the equation x2+y2=1 and check whether left hand side is equal to right hand side.

  02+(1)2=11=1

The above equality holds true, the point (0,1) lie on the graph of the equation.

Substitute the point (12,12) in the equation x2+y2=1 and check whether left hand side is equal to right hand side.

  (12)2+(12)2=112+12=11=1

The above equality holds true, the point (12,12) lie on the graph of the equation.

Substitute the point (32,12) in the equation x2+y2=1 and check whether left hand side is equal to right hand side.

  (32)2+(12)2=134+14=11=1

The above equality holds true so, the point (32,12) lie on the graph of the equation.

Thus, the points (0,1),(12,12) and (32,12) lie on the graph of the equation.

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